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Kruka [31]
3 years ago
8

Two objects that appear to be identical, but are actually non-super imposable mirror images, are said to have the property of __

___.
a. Chirality
b. Polarity
c. Uniqueness
d. Symmetry
e. Nonpolarity
Chemistry
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

= a) chirality

Explanation:

Because chiral molecules has four different atoms bonded to the central atom, hence they rotate plane polarized light and produces non-superimposable mirror images

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How can I calculate the valence electrons of ions?
DIA [1.3K]

First of all, you should know the valence electron of atom.

Then add charge, In case of -ve ion & subtract, in case of +ve ion.

8 0
3 years ago
Each element possesses unique chemical and physical properties.<br> a. True<br> b. False
belka [17]
A. True Because Each element is made up of unique type of atom that has very specific properties
4 0
3 years ago
Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction.
Lynna [10]

The percent yield of CO₂ is 93.3%.

<h3>What is the percent yield of CO₂?</h3>

The percent yield of a substance is given as follows:

  • Percent yield = actual yield/theoretical yield * 100 %

The equation of the reaction is used to determine the theoretical yield.

  • NaHCO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂

Moe ratio of sodium bicarbonate and CO₂ is 1 : 1.

Given that sodium bicarbonate is the limiting reactant, the theoretical yield of CO₂ will be:

Moles of NaHCO₃ reacting = 2.01/84 = 0.0239 moles

Theoretical yield of CO₂ = 0.0239 moles * 22.4L/mol = 0.536 L

Actual yield = 0.50 L

Percent yield = 0.50/0.536 * 100%

Percent yield = 93.3%

In conclusion, the percent yield is the ratio of the actual yield and theoretical yield.

<em>Note that the complete question is given below:</em>

<em>Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction between 2.01 g of sodium bicarbonate and 24.6 mL of 1.5 M acetic acid? They produce 0.50 L of at s.t.p.</em>

<em />

Learn mores about percent yield at: brainly.com/question/8638404

#SPJ1

3 0
2 years ago
Compound X has the formula C8H14. X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form
REY [17]

Answer:

1-Ethyl-3-methylidenecyclopentane  

Step-by-step explanation:

Formula = C₈H₁₄. An alkane has formula C₈H₁₈. ∴ X contains 2 double bonds, 2 rings, or 1 ring and 1 double bond.

X absorbs only 1 mol of hydrogen. ∴ X contains 1 ring and 1 double bond.

Hydrogenation gives 1-ethyl-3-methylcyclopentane.

Ozonolysis gives formaldehyde, so X must contain a =CH₂ group.  

Hydrogenation of X converted the =CH₂ to -CH₃.

X is 1-ethyl-3-methylidenecyclopentane.

You can see the reactions in the image below.

3 0
3 years ago
Given the following information regarding the masses and relative abundances for the isotopes of an element, determine its atomi
Ilia_Sergeevich [38]

Answer:

Average atomic mass = 58.51047 amu

The symbol is Ni

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})+(\frac {\%\ of\ the\ fourth\ isotope}{100}\times {Mass\ of\ the\ fourth\ isotope})+(\frac {\%\ of\ the\ fifth\ isotope}{100}\times {Mass\ of\ the\ fifth\ isotope})

Given that:

For first isotope:

% = 68.274 %

Mass = 57.9353 amu

For second isotope:

% = 26.095 %

Mass = 58.9332 amu

For third isotope:

% = 1.134 %

Mass = 61.9283 amu

For fourth isotope:

% = 3.593 %

Mass = 63.9280 amu

For fifth isotope:

% = 0.904 %

Mass = 63.9280 amu

Thus,  

Average\ atomic\ mass=\frac{68.274}{100}\times {57.9353}+\frac{26.095}{100}\times {58.9332}+\frac{1.134}{100}\times {61.9283}+\frac{3.593}{100}\times {63.9280}+\frac{0.904}{100}\times {63.9280}

Average\ atomic\ mass=39.55474 +15.37861854+0.702266922+2.29693304+0.57790912

Average atomic mass = 58.51047 amu

The symbol is Ni

5 0
4 years ago
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