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Crazy boy [7]
2 years ago
13

A box of mass 64 kg is at rest on a horizontal frictionless surface. A constant horizontal force F~ then acts on the box and acc

elerates it to the right. It is observed that it takes the box 5.4 seconds to travel 32 meters. What is the magnitude of the force?
Physics
1 answer:
iren2701 [21]2 years ago
3 0

Answer:

The correct answer is;

The magnitude of the force is 35.12 N

Explanation:

To solve the question, we note that the friction is zero and the force causes motion of a stationary mass

One of the equations of motion is required such as

v² = u² + 2× a× s

Where

v = Final velocity = 5.93 m/s

u = Initial velocity = 0 m/s , object at rest

a = acceleration

s = distance moved = 32 meters

But v = Distance/Time = 32 m /5.4 s = 5.93 m/s

Therefore

5.93² = 2×a×32

or a = 35.12/ 64 = 0.55 m/s²

Therefore Force F = Mass m × Acceleration a

Where mass m = 64 kg

Therefore F = 64 kg×0.55 m/s² = 35.12 N

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A 62.0 kg sprinter starts a race with an acceleration of 1.44 m/s2. If the sprinter accelerates at that rate for 30 m, and then
Dominik [7]

Answer:

The time taken for the race is 17.20 s.

Explanation:

It is given in the problem that a 62.0 kg sprinter starts a race with an acceleration of 1.44 meter per second square.The initial speed of the sprinter is zero as it starts from the rest.

Calculate the final speed of the sprinter.

The expression for the equation of the motion is as follows;

v^{2}-u^{2}= 2as

Here, u is the initial speed, v is the final speed, a is the acceleration and s is the distance.

Put u= 0, s=30 m and a= 1.44 ms^{-2}.

v^{2}-(0)^{2}= 2(1.44)(30)

v= 9.3 m^{-1}

Calculate time taken to cover 30 m distance.

The expression for the equation of motion is as follows;

s=ut+\frac{(1)}{2}at^2

Put u= 0, s=30 m and a= 1.44 ms^{-2}.

30=(0)t+\frac{(1)}{2}(1.44)t^2

t=6.45 s

Calculate the time taken to complete his race.

T= t+t'

Here, t is the time taken to cover 30 m distance and t' is the time taken to cover 100 m distance.

T=6.45+\frac{s'}{v}

Put s= 30 m, v= 9.3 m^{-1} and s'= 100 m.

T=6.45+\frac{(100)}{9.3}

T= 17.20 s

Therefore, the time taken for the race is 17.20 s.

6 0
3 years ago
A storm 10.0 km in diameter has wind speeds of 10.0 m/s. What is its angular velocity in radians per second
Aloiza [94]

Answer:

The value is w= 2*10^{-3} \  rad/s

Explanation:

From the question we are told that

  The diameter of the storm is  d =  10.0 \  km  =  10 000 \  m

   The wind speed is  v  =  10.0 \  m/s

   

Generally the radius is mathematically represented as

       r =  \frac{d}{2}

=>  r =  \frac{10000}{2}

=>    r =  5000 \ m

Generally the angular velocity is mathematically represented as  

        w= \frac{v}{r}

=>     w= \frac{10}{5000}

=>     w= 2*10^{-3} \  rad/s

3 0
2 years ago
A. Blue light has higher energy than red light. Write 3 - 4 sentences comparing these electromagnetic waves with respect to the
frosja888 [35]

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

E = \frac{hc}{\lambda} = h\nu

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

\nu = \frac{c}{\lambda}

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current

5 0
2 years ago
Read 2 more answers
WILL BE BRAINLIEST <br> HELP!!!
ivolga24 [154]

Answer:

(8.0÷6.0)×10[(-2)-(-3)]

6 0
2 years ago
In an experiment, 1 mol of propane is burned to form carbon dioxide and water.
Natalija [7]

Answer:

5 moles of O2are required, you can see it in your equation.

5 0
2 years ago
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