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gtnhenbr [62]
3 years ago
11

When applied behavior analysis is used properly what happens???​

Physics
1 answer:
evablogger [386]3 years ago
4 0

Answer:

Applied Behavior Analysis therapy (ABA) is a type of intensive therapy that focuses on the principles and techniques of learning theory to help improve social behavior. ABA therapy helps to (1) develop new skills, (2) shape and refine previously learned skills, and (3) decrease socially significant problem behaviors.

Explanation:

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The student makes a single pile of the 500 sheets of paper. Which a metre rule, she measured the height of the pile. The height
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Answer:  please see attached work.

Explanation:  please see attached work.  Assuming 500 sheets of paper = 20 lb.  (typicical value).  

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Why is warm up important?
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An isolated charged point particle produces an electric field with magnitude E at a point 2 m away. At a point 1 m from the part
guajiro [1.7K]

Explanation:

The electric field at a distance r from the charged particle is given by :

E=\dfrac{kq}{r^2}

k is electrostatic constant

if r = 2 m, electric field is given by :

E_1=\dfrac{kq}{(2)^2}\\\\=\dfrac{kq}{4}\ .....(1)

If r = 1 m, electric field is given by :

E_2=\dfrac{kq}{r_2^2}\\\\=\dfrac{kq}{1}\ ....(2)

Dividing equation (1) and (2) we get :

\dfrac{E_1}{E_2}=\dfrac{\dfrac{kq}{4}}{kq}\\\\\dfrac{E_1}{E_2}=\dfrac{1}{4}\\\\E_2=4\times E_1

So, at a point 1 m from the particle, the electric field is 4 times of the electric field at a point 2 m.

4 0
3 years ago
A student attempted to measure the specific latent heat of vaporisation of water.
tensa zangetsu [6.8K]

Answer:

The latent heat of vaporization of water is 2.4 kJ/g

Explanation:

The given readings are;

The first (mass) balance reading (of the water) in grams, m₁ = 581 g

The second (mass) balance reading (of the water) in grams, m₂ = 526 g

The first joulemeter reading in kilojoules (kJ), Q₁ = 195 kJ

The second joulemeter reading in kilojoules (kJ), Q₂ = 327 kJ

The latent heat of vaporization = The heat required to evaporate a given mass water at constant temperature

Based on the measurements, we have;

The latent heat of vaporization = ΔQ/Δm

∴ The latent heat of vaporization of water = (327 kJ - 195 kJ)/(581 g - 526 g) = 2.4 kJ/g

The latent heat of vaporization of water = 2.4 kJ/g

6 0
3 years ago
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