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2 years ago

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When applied behavior analysis is used properly what happens???

1 answer:

evablogger [386]2 years ago

4 0

Answer:

Applied Behavior Analysis therapy (ABA) is a type of intensive therapy that focuses on the principles and techniques of learning theory to help improve social behavior. ABA therapy helps to (1) develop new skills, (2) shape and refine previously learned skills, and (3) decrease socially significant problem behaviors.

Explanation:

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A compact car moving at 60 m/s has 320,000 J of kinetic energy. What is its mass?

joja [24]

Answer:

320,000J

Explanation:

mass=320,000J

8 0

2 years ago

Two children of mass 27 kg and 51 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c

Flauer [41]

Answer:

2.62 m

Explanation:

Let the small child sit at a distance x from the pivot.

The distance of big child from the pivot is 4 - x .

By using the concept of moments.

Clockwise moments = anticlockwise moments

27 x = 51 ( 4 - x )

27 x = 204 - 51 x

78 x = 204

x = 2.62 m

8 0

2 years ago

The angular velocity of a process control motor is (13−12t2) rad/s, where t is in seconds. Part A At what time does the motor re

mihalych1998 [28]

Answer:

Explanation:

Given

$\omega =13-\frac{1}{2}\cdot t^2$

Motor reverse its direction when \omega =0

$13-0.5t^2=0$

$26=t^2$

$t=\sqrt{26}=5.099\approx 5.1 s$

(b)

$\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega$

$\int d\theta =\int_{0}^{5.1}\omega dt$

$\int d\theta =\int_{0}^{t}(13-.05t^2)dt$

$\theta =(13t-0.1667\times t^3)_0^{5.1}$

$\theta =44.192^{\circ}$

4 0

2 years ago

What is the mean of 22, 72, 79, 72, and 70

Nataly_w [17]

Answer:

63

Explanation:

You first have to add all the numbers together.

22+72+79+72+70 = 315

You divide the total by the amount of numbers (5)

315/5 = 63

The mean is 63

7 0

2 years ago

A 2 kg object traveling at 5 m s on a frictionless horizontal surface collides head-on with and sticks to a 3 kg object initiall

Svetlanka [38]

Answer: (d)

Explanation:

Given

Mass of object $m=2\ kg$

Speed of object $u=5\ m/s$

Mass of object at rest $M=3\ kg$

Suppose after collision, speed is v

conserving momentum

$\Rightarrow mu+0=(m+M)v\\\\\Rightarrow v=\dfrac{2\times 5}{2+3}\\\\\Rightarrow v=2\ m/s$

Initial kinetic energy

$k_1=\dfrac{1}{2}\times 2\times 5^2\\\\k_1=25\ J$

Final kinetic energy

$k_2=\dfrac{1}{2}\times (2+3)\times 2^2\\\\k_2=10\ J$

So, it is clear there is decrease in kinetic energy . Thus, energy decreases and velocity becomes 2 m/s.

4 0

2 years ago