I’m don’t kill me if I’m wrong but I think it’s high melting point
Only one molecule have <u>sp2 </u>hybridization on central atom and that is <u>SO₂</u>.
<u>XeCl₂</u> have <u>sp3d </u>hybridization.
<u>OCl₂</u> have <u>sp3 </u>hybridization.
<u>HCN </u>have <u>sp </u>hybridization.
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
Hybridization intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.
Learn more about hybridization here:- brainly.com/question/22765530
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Answer:

Explanation:
We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
Mᵣ: 44.01
C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O
n/mol: 1.5
1. Calculate the moles of CO₂
The molar ratio is 3 mol CO₂:1 mol C₃H₈

2. Calculate the mass of CO₂.

<u>Answer:</u> The rate law of the reaction is ![\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BHgCl_2%5D%5BC_2O_4%5E%7B2-%7D%5D%5E2)
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:

Rate law expression for the reaction:
![\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BHgCl_2%5D%5Ea%5BC_2O_4%5E%7B2-%7D%5D%5Eb)
where,
a = order with respect to 
b = order with respect to 
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Expression for rate law for third observation:
....(3)
Expression for rate law for fourth observation:
....(4)
Dividing 2 from 1, we get:

Dividing 2 from 3, we get:

Thus, the rate law becomes:
![\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BHgCl_2%5D%5E1%5BC_2O_4%5E%7B2-%7D%5D%5E2)