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3 years ago

Does the eruption from a volcano represent force

Physics

1 answer:

kkurt [141]3 years ago

6 0

Answer:

Yes, because of the force of gas exploding the volcano from pressure is a force.

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A 3.5 x 10-6 C charge is located 0.28 m from a 2.8 x 10-6 C charge. What is the magnitude of the force being exerted on the smal

Margarita [4]

The electrostatic force between two charges is given by Coulomb's law:
$F=k_e \frac{q_1 q_2}{r^2}$
where
ke is the Coulomb's constant
q1 is the first charge
q2 is the second charge
r is the separation between the two charges

By substituting the data of the problem into the equation, we can find the magnitude of the force between the two charges:
$F=(8.99 \cdot 10^{9} Nm^2C^{-2} ) \frac{(3.5 \cdot 10^{-6} N/C)(2.8 \cdot 10^{-6}N/C)}{(0.28m)^2}=1.2 N$

7 0

3 years ago

Mengapa indra peraba tidak dapat digunakan untuk membandingkan suhu dengan tepat?

Debora [2.8K]

Answer it ur self if u have internet

3 0

3 years ago

I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXT

ratelena [41]

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop, IR = E- V

IR = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

IR = V

$R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms$

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

7 0

3 years ago

Identify the energy transformations in the image below:

Masteriza [31]

Answer:

B. Chemical to Electrical to Radiant

Explanation:

8 0

2 years ago

Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters

Vika [28.1K]

Hi there!

Recall the following relationships:

$W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}$

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

$W = 50(10)(8) = 4000 J$

Now, divide by the time to solve for power:

$P = \frac{4000}{5} = \boxed{800W}$

**W is the unit for power (Watts). Be careful not to get the two confused.

4 0

2 years ago