If the acceleration is constant (negative or positive) the instantaneous acceleration cannot be
Average acceleration: [final velocity - initial velocity ] /Δ time
Instantaneous acceleration = d V / dt =slope of the velocity vs t graph
If acceleration is increasing, the slope of the curve at one moment will be higher than the average acceleration.
If acceleration is decreasing, the slope of the curve at one moment will be lower than the average acceleration.
If acceleration is constant, the acceleration at any moment is the same, then only at constant accelerations, the instantaneuos acceleration is the same than the average acceleration.
Constant zero acceleration is a particular case of constant acceleration, so at constant zero acceleration the instantaneous accelerations is the same than the average acceleration: zero. But, it is not true that only at zero acceleration the instantaneous acceleration is equal than the average acceleration.
That is why the only true option and the answer is the option D. only at constant accelerations.
Answer:
Explanation:
a) because it's immoral as you're trying to convince people of your views when you should be giving both sides of the story so people are able to come up with their own opinions on what you're talking about
Answer:
4.9612 s
Explanation:
Applying,
T = 2π√(L/g)............... Equation 1
Where T = period of the pendulum, L = Lenght of the pendulum, g = acceleration due to gravity of the moon, π = pie.
From the question,
Given: L = 1 m, g = 1.6 m/s²
Constant: π = 3.14
Substitute these values into equation 1
T = 2×3.14×√(1/1.6)
T = 6.28√(0.625)
T = 6.28×0.79
T = 4.9612 s
Each serving gives 3 grams or 12% of daily recommended value. Divide 100% by 12% to get 8.33 servings to obtain the daily recommended value of 25 grams.
Sodium (Na) is very reactive because it does not have a full valence shell.
