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joja [24]
3 years ago
6

Does the eruption from a volcano represent force

Physics
1 answer:
kkurt [141]3 years ago
6 0

Answer:

Yes, because of the force of gas exploding the volcano from pressure is a force.

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Which of the following would add more resistance? Check all that apply.
Blababa [14]

Answer:C. E.

Explanation:

4 0
3 years ago
A 40.0 turn coil of wire of radius 3.0 cm is placed between the poles of an electromagnet. The field increases from 0 to 0.75 T
nadezda [96]

Answer:

Induced emf, V=3.76\times 10^{-4}\ V

Explanation:

We have,

Number of turns in the coil, N = 40

Radius of coil, r = 3 cm = 0.03 m

The field increases from 0 to 0.75 T at a constant rate in a time interval of 225 s.

It is required to find the magnitude of the induced emf in the coil if the field is perpendicular to the plane of the coil. The induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi=NBA\cos\theta, is magnetic flux

\epsilon=NA\dfrac{dB}{dt}\\\\\epsilon=\dfrac{40\times \pi (0.03)^2\times (0.75-0)}{225}\\\\\epsilon=3.76\times 10^{-4}\ V

So, the magnitude of induced emf is 3.76\times 10^{-4}\ V.

7 0
3 years ago
Which shows the correct reflected ray? Question options: A B C D
Darya [45]

Answer:

D

Explanation:

The law of reflection states that:

- The incident ray and the reflected ray lie on the same plane

- The angle of reflection is equal to the angle of incidence

The angle of incidence is the angle between the direction of the incident ray and the normal to the surface, while the angle of reflection is the angle between the direction of the reflected ray and the normal to the surface.

From the figure, we see that the only situation where the angle of reflection is equal to the angle of incidence is ray D.

6 0
3 years ago
The field inside a charged parallel-plate capacitor is __________.
Bess [88]
<span>Uniform. A parallel plate capacitor is a simple arrangement of electrodes and dielectric to form a capacitor. Here two parallel conductive plates are used as electrodes with a medium or dielectric in between them. Charge separation in a parallel-plate capacitor causes an internal electric field, which is uniform.</span>
5 0
4 years ago
Read 2 more answers
An AC source operating at 59 Hz with a maximum voltage of 170 V is connected in series with a resistor (R = 1.2 kΩ) and an induc
Alexxandr [17]

I = V/Z

V = voltage, I = current, Z = impedance

First let's find the total impedance of the circuit.

The impedance of the resistor is:

Z_{R} = R

R = resistance

Given values:

R = 1200Ω

Plug in:

Z_{R} = 1200Ω

The impedance of the inductor is:

Z_{L} = j2πfL

f = source frequency, L = inductance

Given values:

f = 59Hz, L = 2.4H

Plug in:

Z_{L} = j2π(59)(2.4) = j889.7Ω

Add up the individual impedances to get the Z, and convert Z to polar form:

Z = Z_{R} + Z_{L}

Z = 1200 + j889.7

Z = 1494∠36.55°Ω

I = V/Z

Given values:

V = 170∠0°V (assume 0 initial phase)

Z = 1494∠36.55°Ω

I = 170∠0°/1494∠36.55°Ω

I = 0.1138∠-36.55°A

Round the magnitude of I to 2 significant figures and now you have your maximum current:

I = 0.11A

5 0
3 years ago
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