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myrzilka [38]
3 years ago
6

Define an ideal gas and explain under which conditions you may reasonably approximate a real gas as an ideal gas. Also mention c

onditions under which it would be inappropriate to approximate a real gas as an ideal gas. (you may need to use a search engineto help you out here)
Chemistry
1 answer:
TEA [102]3 years ago
5 0

Answer:

High temperature and low pressure

Explanation:

According to the kinetic molecular theory, gases are composed of small particles called molecules which are in constant motion.

At high temperature and low pressure, gas molecules possess high kinetic energy and move at high velocities hence intermolecular interaction is almost none existent and real gases approach the behavior of ideal gases.

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What is the word equation of 1 H2 + 1 Cl2 → 2 HCI
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1 dihydrogen reacts with 1 chlorine to form two hydrogen chloride (edit: hydrogen chloride is also referred to as hydrochloric acid)

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6 0
3 years ago
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Using the equation below, if you have 4.3 mol of nitrogen tribromide and
ankoles [38]

Answer:

sodium hydroxide is the limiting reactant

Explanation:

The first step is usually to put down the balanced reaction equation. This is the first thing to do when solving any problem related to stoichiometry. The balanced reaction equation serves as a guide during the solution.

2NBr3 + 3NaOH = N2 + 3NaBr + 3HOBr

Let us pick nitrogen gas as our product of interest. Any of the reactants that gives a lower number of moles of nitrogen gas is the limiting reactant.

For nitrogen tribromide

From the balanced reaction equation;

2 moles of nitrogen tribromide yields 1 mole of nitrogen gas

4.3 moles of nitrogen tribromide will yield 4.3 ×1/ 2 = 2.15 moles of nitrogen gas

For sodium hydroxide;

3 moles of sodium hydroxide yields 1 mole of nitrogen gas

5.9 moles of sodium hydroxide yields 5.9 × 1/ 3= 1.97 moles of nitrogen gas

Therefore, sodium hydroxide is the limiting reactant.

8 0
3 years ago
1. Use the following equation:
fenix001 [56]

Answer:

7.28 mol

Explanation:

2 NaOH +  H₂SO₄ =  2 H₂O +  Na₂SO₄ -------------------(1)

mole fraction for the reaction is;

2 : 1 = 2 : 1

Number of moles of H₂SO₄ = 7.28 mol

1 mol of H₂SO₄ shall form 1 mole of Na₂SO₄

therefore,

7.28 mol of H₂SO₄ shall form 7.28 mole of Na₂SO₄

8 0
3 years ago
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