Answer:
CICUO3
Explanation:
copper 1 chlorate is made up of copper ion and a polyatomic ion of chlorine and oxygen
Answer:
Which best describes a difference between energy transformations in power plants and dams? Only power plants use fossil fuels to transform energy. Only dams use fission to generate thermal energy. ... Only dams use mechanical energy to produce electricity.
Explanation:
HOPE THIS HELP
PICK ME AS THE BRAINLIEST
Don't take my word for it but I think it is
1: proteins
2: energy from the sun, carbon dioxide, and water
3: this one is confusing me but I think it would be nutrients from food and oxygen
4: water
Again these are attempts I can't prove these
Explanation:
The given data is as follows.
= 0.483,
= 0.173 M,
= 0.433 M,
= 0.306 M,
= 9.0 atm
According to the ideal gas equation, PV = nRT
or, P =
Also, we know that
Density = ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
So, P = MRT
and, M = ![\frac{P}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BRT%7D)
= ![\frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}](https://tex.z-dn.net/?f=%5Cfrac%7B9.0%20atm%7D%7B0.0820%20L%20atm%2Fmol%20K%20%5Ctimes%20298%20K%7D)
= ![\frac{9.0}{24.436}](https://tex.z-dn.net/?f=%5Cfrac%7B9.0%7D%7B24.436%7D)
= 0.368 mol/L
Now, we will calculate the cell potential as follows.
E = ![E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}](https://tex.z-dn.net/?f=E%5E%7Bo%7D%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5BCo%5E%7B2%2B%7D%5D%5E%7B2%7D%5BCl_%7B2%7D%5D%7D%7B%5BCo%5E%7B3%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%7D)
= ![0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}](https://tex.z-dn.net/?f=0.483%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%20%5Cfrac%7B%280.433%29%5E%7B2%7D%280.368%29%7D%7B%280.173%29%280.306%29%5E%7B2%7D%7D)
= ![0.483 - 0.02955 log \frac{0.0689}{0.0162}](https://tex.z-dn.net/?f=0.483%20-%200.02955%20log%20%5Cfrac%7B0.0689%7D%7B0.0162%7D)
= ![0.483 - 0.02955 \times 0.628](https://tex.z-dn.net/?f=0.483%20-%200.02955%20%5Ctimes%200.628)
= 0.483 - 0.0185
= 0.4645 V
Thus, we can conclude that the cell potential of given cell at
is 0.4645 V.