The width of the aquarium is 0.1625 ft.
Step-by-step explanation:
Given,
The length (l) of the aquarium = 2 ft
Height (h) = 1.5 ft
The capacity of water it holds = 3.75 gallons
That means the volume (V) = 3.75 gallon
To find the width(b) of the aquarium.
Formula
- The volume of a cuboid with l as length, b as width and h as height = lbh
So,
V = 3.75×0.13 cube ft
According to the problem,
2×1.5×b = 3.75×0.13
or, b = (3.75×0.13)÷(2×1.5)
or, b = 0.1625 ft
Hence,
The width of the aquarium is 0.1625 ft.
Answer:
x=4.
Step-by-step explanation:
Let's solve your equation step-by-step.
5/15=x/ x+8
Step 1: Cross-multiply.
5/15=x/ x+8
5*(x+8)=x*(15)
5x+40=15x
Step 2: Subtract 15x from both sides.
5x+40−15x=15x−15x
−10x+40=0
Step 3: Subtract 40 from both sides.
−10x+40−40=0−40
−10x=−40
Step 4: Divide both sides by -10.
−10x−10=−40−10
Then your answer will be x=4.
Answer:
x +3
____
x
*line is a fraction line*
Answer:
{2, 8}
Step-by-step explanation:
We want to find x for ...
15 = 4|x -5| +3
12 = 4|x -5| . . . . subtract 3
3 = |x -5| . . . . . . divide by 4
±3 = x -5 . . . . . . show the meaning of absolute value
5 ±3 = x = {2, 8} . . . . . add 5
The values of x for which f(x) = 15 are 2 and 8.
I wont solve this because Im to lazy, but I do recommend some of these sites to help you with your problem. MathPapa Algebra Calculator and PhotoMath. Hope this helps.
