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sergejj [24]
3 years ago
5

The instrument pictured below is a resistometer aerometer manometer barometer

Chemistry
1 answer:
puteri [66]3 years ago
8 0

Answer:

barometer

Explanation:

this is a barometer because It has bars and it measures how tall an object is

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Write a net ionic equation for the overall reaction that occurs when aqueous solutions of hydrosulfuric acid (H2S) and sodium hy
erica [24]

Answer:

H2S(g) + 2OH^-(aq) -------->  S^2-(aq) + 2H2O(l)

Explanation:

We know that the net ionic equation shows the major reaction that occurs in the reaction system.

The molecular reaction equation is;

H2S(g) + 2NaOH(aq) ------> Na2S(aq) + 2H2O(l)

The complete ionic equation is;

H2S(g) + 2Na^+(aq) + 2OH^-(aq) --------> 2Na^+(aq) + S^2-(aq) + 2H2O(l)

Net ionic equation;

H2S(g) + 2OH^-(aq) -------->  S^2-(aq) + 2H2O(l)

3 0
3 years ago
When a hydrochloric acid solution is combined with a potassium hydroxide solution, an acid-base reaction occurs Write a balanced
Svetach [21]

Answer:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

Explanation:

Hydrochloric acid is an acid because it releases H⁺ in an aqueous solution.

Potassium hydroxide is a base because it releases OH⁻ in an aqueous solution.

When an acid reacts with a base they form a salt and water. This is a neutralization reaction. The neutralization reaction between hydrochloric acid and potassium hydroxide is:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

7 0
4 years ago
An excess of mg(s) is added to 100.ml of 0.400 m hcl. at 0c and 1 atm pressure, what volume of h 2 (g) can be obtained?
ra1l [238]
The balanced equation for the reaction between Mg and HCl is as follows
Mg + 2HCl --> MgCl₂ + H₂
stoichiometry of HCl to H₂ is 2:1

number of HCl moles reacted - 0.400 mol/L x 0.100 L = 0.04 mol of HCl
since Mg is in excess HCl is the limiting reactant 
number of H₂ moles formed - 0.04/2 = 0.02 mol of H₂

we can use ideal gas law equation to find the volume of H₂
PV = nRT 
where 
P - pressure - 1 atm x 101 325 Pa/atm = 101 325 Pa
V - volume
n - number of moles - 0.02 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 0 °C + 273 = 273 K
substituting these values in the equation 

101 325 Pa x V = 0.02 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K
V = 448 x 10⁻⁶ m³
V = 448 mL 
therefore answer is 
c. 448 mL 
5 0
3 years ago
..........quwcwfeebthtrf
monitta

Answer:

wsdefrgtyuiop

Explanation:

5 0
3 years ago
Dew forming on grass is an example of condensation true or fales and explain
exis [7]
True becuase dew is coming out of the air which if you look at a glass of water it has condensation on it becuase it is hot
7 0
4 years ago
Read 2 more answers
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