F = 2820.1 N
Explanation:
Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as
Fnet = ma = 0 (a = 0 no sliding)
= F - mgsin15°
= 0
or
F = mgsin15°
= (120 kg)(9.8 m/s^2)sin15°
= 2820.1 N
Your pendulum does a complete swing in 1.9 seconds. You want to SLOW IT DOWN so it takes 2.0 seconds.
Longer pendulums swing slower.
You need to <em>make your pendulum slightly longer</em>.
If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom. You can add weight or cut some off, and it won't change the speed a bit.
given that initial velocity is
deceleration is given as
now we have to find the distance covered in 16 s
so it will cover 137.6 m distance
part b)
in order to find the final speed
so its speed will be 6.2 m/s
Work = (force) x (distance)
(550 newtons) x (0.5 meter) = 275 joules each lift .
(275 joules/lift) x (10 lifts) = 2,750 joules of work all together.
Power = (work done) / (time to do the work)
= (2,750 joules) / (20 seconds)
= 137.5 watts . (about 0.18 horsepower)
Answer:
no way man i dontknow the answer man
Explanation:
