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Allushta [10]
3 years ago
7

A pickup truck is carrying a 10.0 kg toolbox, but the tailgate of the truck is missing, so the box can slide out if it starts mo

ving. The coefficients of static and kinetic friction between the toolbox and the truck bed are 0.31 and 0.18, respectively. Assume that the truck bed is horizontal. What is the shortest time the truck could take to accelerate from rest to 13.2 m/s without causing the toolbox to slide

Physics
1 answer:
scoray [572]3 years ago
5 0

Answer: The shortest time the truck could take is 4.34 secs

Explanation: Please see the attachments below

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The actual mechanical advantage of any machine is its__________divided by its________________
zaharov [31]

Answer: Load divided by it effort

Explanation:

Mechanical advantage of any machine is its load divided by its effort

4 0
3 years ago
Which of these discoveries contradict components of Dalton’s atomic theory? Check all of the boxes that apply. Atoms contain sma
EastWind [94]

Explanation:

According to Dalton's atomic theory, all the atoms are individual, all the atoms of the same element are identical in properties and mass, the compound is formed from two or more kinds of the atoms, all the matter is made up of small atoms and the chemical reaction is a rearrangement of the atoms.

The discoveries which contradicts the components of Dalton's atomic theory from the given discoveries are:

Nuclear reactions can change an atom of one element into an atom of another element.

Atoms of a given element can have different numbers of neutrons.

Atoms contain smaller particles: protons, neutrons, and electrons.

4 0
3 years ago
Read 2 more answers
near the surface of the earth, objects in free fall (but not terminal velocity) experience a. constant distance. b. constant acc
Alenkasestr [34]
<h3><u>Answer;</u></h3>

B. constant acceleration.

<h3><u>Explanation</u>;</h3>
  • Free fall is the type of motion of a body or an object when only gravity is acting on it.
  • <em><u>All objects undergo free fall on the earth surface at the same rate irrespective of their mass. This is because the gravitational field on the surface of the earth 9.8 N/kg, causes and acceleration equivalent to 9.8 m/s/s of any object in free fall motion.</u></em>
  • Therefore,<u> the acceleration of any freely falling object near the surface of the earth is 9.8 m/s².</u>
3 0
4 years ago
Read 2 more answers
A tennis ball is thrown vertically upward with an initial velocity of +6.2 m/s. What will the ball’s velocity be when it returns
anastassius [24]

Answer:

v_{f}=-6.2 m/s

Explanation:

The ball will rise decreasing its speed until it reaches the highest point where its speed will be zero. From this point the tennis ball will begin to fall again, in the free fall the tennis ball will gain speed but now in the opposite direction. When it returns to the same point where it was launched, its speed will be the same as the one that was launched but with the opposite sign.

v_{f}=-6.2 m/s

We can check this using the equation:

v_{f}^2=v_{i}^2+2gh

where v_{i}=+6.2 m/s

ang h is the height, but because the ball returns to the same point where it started, h =0

then

v_{f}^2=v_{i}^2

v_{f}=v_{i}

the initial and final velocity will be the same in number, but we know that the ball is going in the opposite direction, so the final velocity must have the opposite sign from the initial velocity

so if v_{i}=+6.2 m/s,

v_{f}=-6.2 m/s

4 0
3 years ago
An unknown radioactive sample is observed to decrease in activity by a factor of two in a one hour period. What is its half-life
elena55 [62]

Answer:

The half-life is t_{1/2} = 1.005 h

Explanation:

Using the decay equation we have:

A=A_{0}e^{-\lambda t}

Where:

  • λ is the decay constant
  • A(0) the initial activity
  • A is the activity at time t

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that A = \frac{A_{0}}{2}

\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}

0.5=e^{-\lambda*1 h}

Taking the natural logarithm on each side we have:

ln(0.5)=-\lambda

\lambda=0.69 h^{-1}

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

\lambda = \frac{ln(2)}{t_{1/2}}

t_{1/2} = \frac{ln(2)}{\lambda}

t_{1/2} = \frac{ln(2)}{0.69}

t_{1/2} = 1.005 h

I hope it helps you!

6 0
3 years ago
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