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Elan Coil [88]
3 years ago
9

Why is it important to define a frame of reference?

Physics
2 answers:
SOVA2 [1]3 years ago
6 0

It is important to define a frame of reference because motion must be defined relative to something. Hence option(b) is correct.

Further Explanation:

Frame of reference is a framework that is used for observation of physical phenomena. It consists of an observer, a coordinate system and positions with respect to the coordinate system.

(a)

Let us take an example of a trolley moving with velocity u and a man on the ground at rest.

Since, the man's velocity is zero, the relative velocity of trolley with respect to the man is u.

Now, if a man starts to run with speed u and speed of trolley increases to two times of initial velocity u i.e. 2u, the relative velocity of trolley with respect to man is (2u-u=u).

Here, in both the conditions, the relative velocity of trolley with respect to time is same.

Therefore, it is wrong to say that an observer cannot be moving. Hence, option(a) is incorrect.

(b)

Let us take an example of a man on the ground at rest and a trolley moving with the velocity u having an object placed in it. The object will also moves with the velocity u.

For a man, trolley is moving with velocity u but for an object trolley is at rest because there is no relative motion between object and trolley.

Therefore, it is right to say that motion must be defined relative to something. Hence, option(b) is correct.

(c)

Let us take an example of a first object moving with velocity u and a second object moving with velocity v in the opposite direction and a third object is at rest.

The relative velocity of first object with respect to second object is (v+u) and the relative velocity of first object with respect to third object is v.

Here, the relative velocity of an object is different with respect to different object but all the motions are measurable.

Therefore, it is wrong to say that it's impossible to measure motion. Hence, option(c) is incorrect.

(d)

Let us take an example of two trains moving with same velocity in same direction.

Consider a man sitting in one train observes a man running in other train, then the man sitting is said to be stationary observer for the man running. Here, the man is stationary observer while in motion.

Now, if a man standing on the ground at rest will see the man on train, he will be called stationary observer. Here, the man is stationary observer while not in motion.

Therefore, it is wrong to say that a stationary observer is always moving. Hence, option(d) is incorrect.

Learn more:

1. Motion on a rough surface: brainly.com/question/7031524

2. Motion under the gravitational force: brainly.com/question/10934170

3. Principle of conservation of momentum: brainly.com/question/9484203

Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Frame, reference, important, observer, motion, relative, velocity, speed, moving, measure, stationary, example, trolley, man and train.

Dmitry [639]3 years ago
3 0

Motion must be defined relative to something.

Here's an obvious, everyday example:

-- You're in a passenger jet, going to visit grandma on the
coast for the holidays.
-- You're sitting still in your seat, listening to some 'mp3's,
reading a book, and dozing off.
-- At the same time, people on the ground see you flying over
at almost 500 miles per hour.

Are you moving at 500 mph, or are you not moving at all ?

The answer is 'Yes. Both.'. It just depends on who's measuring your speed.

There's no such thing as your "real" speed.  Motion is always
relative to something.  Different reference = different speed.


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Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slid
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A)

the minimum stopping distance for which the load will not slide forward relative to the truck is 14 m

B)

data that were not necessary to the solution are;

a) mass of truck and b) mass of load

Explanation:

Given that;

mass of load m_{LS} = 10000 kg

mass of flat bed m_{FB} = 20000 kg

initial speed of truck v_{0} = 12 m/s

coefficient of friction between the load sits and flat bed μs = 0.5

A) the minimum stopping distance for which the load will not slide forward relative to the truck.

Now, using the expression

Fs,max = μs F_{N}     -------------let this be equation 1

where F_{N} = normal force = mg

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Fs,max = μs mg

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divide through by mass

a_{max} = μs g    ---------- let this be equation 2

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a_{max} = 4.9 m/s²

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v² = u² + 2as

v_{f}² = v_{0}² + 2aΔx

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a is acceleration( - 4.9 m/s² )

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(0)² = (12 m/s)² + 2(- 4.9 m/s² )Δx

0 = 144 m²/s² - 9.8 m/s²Δx

9.8 m/s²Δx = 144 m²/s²

Δx = 144 m²/s² /  9.8 m/s²

Δx = 14 m

Therefore, the minimum stopping distance for which the load will not slide forward relative to the truck is 14 m

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a) mass of truck and b) mass of load

3 0
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