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Mila [183]
3 years ago
11

How many liters of oxygen at 0 ∘c and 760 mmhg (stp) are required to completely react with 4.2 g of aluminum?

Chemistry
1 answer:
Vesnalui [34]3 years ago
3 0

Reaction between aluminium and oxygen can be represented as:

4Al(s) + 3O₂(g) ----->2Al₂O₃(s)

Number of moles of aluminium = Mass of aluminium/ Molar mass of aluminium

=4.2g /26.981 g / mol

=0.155 mol

The equation shows that these react with 0.155 * 3/4 moles of O2 = 0.11 moles of O2.

1 mole of O2 at STP occupies 22.4 liter

volume of O2 = 0.11 moles ×22.4 liters / mol

= 2.61 liter of O2.

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What is magnesium used for in its pure form
Sloan [31]

Answer: The pure metal has low structural strength, magnesium is mainly  used in the form of alloys- principally with 10% or less of aluminum, zinc, and manganese- to improve it's hardness, tensile strength, and ability to be cast, welded, and machined.

I hope this really helps you!!! :) And Have a fantastic day!!!

 

6 0
4 years ago
What is the potential energy of a 2 kg plant that is on a windowsill 1.3 m high
gulaghasi [49]

Answer:

P.E = 25.48 J

Explanation:

Given data:

Mass = 2 Kg

Height = 1.3 m

Potential energy = ?

Solution:

Formula:

P.E = m . g . h

P. E = potential energy

m = mass in kilogram

g = acceleration due to gravity

h = height

Now we will put the values in formula.

P.E = m . g . h

P.E = 2 Kg . 9.8 m /s² . 1.3 m

P.E = 25.48 Kg. m² / s²

 Kg. m² / s² = J

P.E = 25.48 J

8 0
4 years ago
Read 2 more answers
An iron block of mass 18 kg is heated from 285 K to 318 K. If 267.3 kJ is required, what is the specific heat of iron? A. 450.00
valkas [14]

Answer:

  • <u>Option A. 450.00</u>

Explanation:

<u>1) Data:</u>

a) m = 18 kg

b) T₁ = 285 K

c) T₂ = 318 K

d) Q = 267.3 kJ

e) S = ?

<u>2) Principles and equations</u>

The specific heat of a substance is the amount of heat energy absorbed to increase the temperature of certain amount (gram, kg, or moles, depending on the definition or units) of the substance in 1 ° C or 1 K.

The mathematical relation between the specific heat and the heat energy absorbed is:

  • Q = m × S × ΔT

Where,

  • Q is the heat absorbed,
  • S is the specific heat, and
  • ΔT is the temperature increase (T₂ - T₁)

<u>3) Solution:</u>

<u>a) Substitute the data into the equation:</u>

  • 267.3 kJ = 18 kg × S × (318 K - 285 K)

<u>b) Solve for S and compute:</u>

  • S = 267.3 kJ / (18 kg × 33 K) = 0.45 kJ / (Kg . K)

The options have not units, but I notice that the first answer is 1,000 times the answer I obtained, so I will make a conversion of units.

<u>c) Convert to J /( kg . k):</u>

  • 0.45 kJ / (Kg . K) × 1,000 J / kJ = 450 J / (kg . K)

Now we can see that the option A is is the answer, assuming the units.

6 0
4 years ago
PLEASE HELP CHEMITRY!
Delicious77 [7]

Answer:

.

Explanation:

5 0
3 years ago
...............………...mkmlkml;m
bagirrra123 [75]

Answer:

390

Explanation:

Specific heat capacity= heat/mass × temperature

x = 2925 \div 0.5 \times 15 = 390

Remember you convert gram into kilogram and 1 gram =0.001 kilogram

5 0
3 years ago
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