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Assoli18 [71]
3 years ago
13

Can people help me with this

Mathematics
2 answers:
marishachu [46]3 years ago
6 0
3) 21,070
5) 600
6) 265
I couldn't see #4
Hoped this helped!
viva [34]3 years ago
5 0
3. 21,070 

4. 105 pounds more

5. 24    

6. 265 times for 5 seconds
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expression

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Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
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probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

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P(B3) = ⅓

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P(B1) = ⅓

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P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

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Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

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P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

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P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

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I hope this helps you

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