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Kay [80]
3 years ago
7

What mass of ammonium thiocyanate must be used if it is to react completely with 6.5 g barium hydroxide octahydrate?

Chemistry
1 answer:
Molodets [167]3 years ago
6 0
<span>The reaction equation is:
Ba(OH)</span>₂<span>*8H</span>₂<span>O + 2NH</span>₄<span>SCN(s) </span>→<span> Ba(SCN)</span>₂<span>(s) + 10H</span>₂<span>O(l) + 2NH</span>₃<span> (g)

The molecular mass of barium hydroxide octahydrate is 315 grams /mol.
We determine the number of moles of barium hydroxide octahydrate:
moles = mass / Mr
moles = 6.5 / 315
moles = 0.02 mol

Using the equation, we can determine that the moles of ammonium thiocyanate required are:
2 * 0.02 = 0.04 mol

The molecular weight of ammonium thiocyanate is 76.1 grams / mol

Weight = moles * Mr
Weight = 0.04 * 76.1
Weight = 3.04 grams


3.04 grams of ammonium thicyanate are required.</span>
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Explanation:

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In this case, since the entropy of vaporization is computed in terms of the heat of vaporization and the temperature as:

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