How many moles of CCl4 are in 3.55L

1 answer:

6 0

Answer: 0.16 moles

Explanation: According to Avogadro's law, 1 mole of every gas at STP occupies a volume of 22.4 Liters.

Given: Volume occupied = 3.55 L

From Avogadro's law,

22.4 L of $CCl_4$ corresponds to= 1 mole

3.55 L of $CCl_4$ correspond to= $\frac{1}{22.4}\times 3.55=0.16moles$

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