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3 years ago

Suppose you increase your walking speed from 4 m/s to 12 m/s in a period of 2 s. What is your acceleration?

Physics

2 answers:

Romashka [77]3 years ago

7 0

The answer is 32 meter per second square.

Karo-lina-s [1.5K]3 years ago

6 0

You should write ' 4 ' in the first box,
and ' m/s² ' in the second box.

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What is the mass of a truck if it is accelerating at a rate of 5 m/s2 and hits a parked car with a

sineoko [7]

Answer:

<h3>The answer is 2800 kg</h3>

Explanation:

The mass of the truck can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{14000}{5} \\$

We have the final answer as

Hope this helps you

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3 years ago

You are standing 10 meters from a light source. Then, you back away from the light source until you are 20 meters away from it.

aliya0001 [1]

From my new perspective, the new intensity of the
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3 years ago

Read 2 more answers

A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equa

ivann1987 [24]

Answer:

The moment of inertia of the wheel is 0.593 kg-m².

Explanation:

Given that,

Force = 82.0 N

Radius r = 0.150 m

Angular speed = 12.8 rev/s

Time = 3.88 s

We need to calculate the torque

Using formula of torque

$\tau=F\times r$

$\tau=82.0\times0.150$

$\tau=12.3\ N-m$

Now, The angular acceleration

$\dfrac{d\omega}{dt}=\dfrac{12.8\times2\pi}{3.88}$

$\dfrac{d\omega}{dt}=20.73\ rad/s^2$

We need to calculate the moment of inertia

Using relation between torque and moment of inertia

$\tau=I\times\dfrac{d\omega}{dt}$

$I=\dfrac{I}{\dfrac{d\omega}{dt}}$

$I=\dfrac{12.3}{20.73}$

$I= 0.593\ kg-m^2$

Hence, The moment of inertia of the wheel is 0.593 kg-m².

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3 years ago

PLZ WHAT I DOO<br> I BROKE A WINDOW WHAT I DO

Hatshy [7]

Hmmmm, you either tell your parent, try to fix it, or blame it on the dog with a baseball bat that always comes on your yard and tries to eat you.

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3 years ago

Suppose a 78 kg person is bouncing on a bathroom scale which has a force constant of 1.5 × 106 n/m. 50% part (a) what is the max

elena55 [62]

m = mass of the person bouncing = 78 kg

k = spring constant of the bathroom scale = 1.5 x 10⁶ N/m

v = maximum velocity of the person

A = maximum compression of the spring of scale = 0.115 cm = 0.00115 m

h = height gained at maximum speed = A = 0.00115 m

Using conservation of energy

spring potential energy = kinetic energy + gravitational potential energy

(0.5) k A² = (0.5) m v² + m g h

k A² = m v² + 2 m g h

(1.5 x 10⁶) (0.00115)² = (78) v² + 2 (78) (9.8) (0.00115)

v = 0.0538 m/s

8 0

3 years ago