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patriot [66]
3 years ago
10

The balanced reaction equation for combustion of heptane, C7H16, is

Chemistry
2 answers:
Allisa [31]3 years ago
3 0

Answer: m = 11.2 g C7H16

Explanation: First convert the mass of CO2 to moles. Then do the mole ratio between CO2 and C7H16 which is 7:1. Finally convert the moles of C7H16 to the mass of C7H16.

Solution attached.

zubka84 [21]3 years ago
3 0

Answer:

Mass of C7H16 burnt = 13.22g

Explanation:

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In general, the value of the equilibrium constant for a chemical reaction does NOT depend on_________.
mart [117]

Answer: Option (B) is the correct answer.

Explanation:

Equilibrium constant is defined as the relationship present between the amounts of products and reactants which are there at equilibrium in a reversible chemical reaction at a given temperature.

For example,     A + B \rightleftharpoons C + D

Mathematically,     K_{eq} = [C][D]

As the value of equilibrium constant depends on rate constants of the forward and reverse reactions. And, this rate of reaction also changes with change in pressure and temperature.

Therefore, it will also lead to change in equilibrium constant but it does not depend on initial amount pf reactants.

Thus, we can conclude that in general, the value of the equilibrium constant for a chemical reaction does NOT depend on the initial amounts of reactants present.

4 0
2 years ago
What is the molarity of a solution that contains 125 g nacl in 4.00 l solution?
bogdanovich [222]

Answer:

[NaCl[ = 0.535M

Explanation:

We determine the moles of solute:

125 g . 1 mol/ 58.45 g = 2.14 moles

Molarity (mol/L) → 2.14 mol / 4L → 0.535M

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3 years ago
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Fynjy0 [20]
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The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.
garik1379 [7]

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day      = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}

Substituting the above values in it we get

\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade

Therefore the temperature drop is -61°Centigrade.

4 0
3 years ago
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