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My name is Ann [436]
3 years ago
10

WILL GIVE BRAINLIEST

Chemistry
2 answers:
nata0808 [166]3 years ago
6 0

Answer:

Density= 0.4412g/cm^3

Explanation:

When finding density the formula is mass divided by volume. So the mass of 15g divided by 34cm^3 equals to the density of 0.4412g/cm^3.

Lynna [10]3 years ago
3 0
Density is 0.4412g/cm^3
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calculate δg o for each reaction using δg o f values: (a) h2(g) i2(s) → 2hi(g) 2.6 kj (b) mno2(s) 2co(g) → mn(s) 2co2(g) kj (c)
Reika [66]

(a)The change in Gibbs free energy for the reaction has been 2.6 kJ/mol.

(b) The change in Gibbs free energy for the reaction has been -49.3 kJ/mol.

(c) The change in Gibbs free energy for the reaction has been 91.38 kJ/mol.

6 0
2 years ago
What is the mass of ethanol thats exacly fills a 200.0ml container
yaroslaw [1]

Answer:

158g

Explanation:

3 0
3 years ago
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6 0
2 years ago
What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

3 0
3 years ago
How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)
polet [3.4K]

Answer:

375.2 kJ

Explanation:

  • H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then <u>state a rule of three</u>:

  • 2 mol HF --------  536 kJ
  • 1.4 mol HF --------- X

And <u>solve for X</u>:

  • X = 1.4 mol * 536 kJ / 2 mol
  • X = 375.2 kJ
7 0
3 years ago
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