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Romashka [77]
3 years ago
7

Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a

sample of sulfur hexafluoride produces 4.45 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produces 4.43 g of fluorine and 1.87 g of sulfur. Calculate the mass of fluorine per gram of sulfur for each sample and show that these results are consistent with the law of multiple proportion.
Chemistry
2 answers:
bija089 [108]3 years ago
7 0

Answer:

For sulfur hexafluoride: the mass of fluorine per gram of sulfur  is 3.56

For sulfur tetrafluoride: the mass of fluorine per gram of sulfur  is 2.369

these results are consistent with the law of multiple proportion.

Explanation:

the solution is in the attached Word file

Download docx
snow_tiger [21]3 years ago
5 0

Answer:

a)

b)

Explanation:

Sample of sulfur hexafluoride SF₆

4.45 g F / 1.25 g S = 3.56

There is a mass ratio of fluorine to sulfur of 3.51 to 1.

Sample of sulfur tetrafluoride SF₄

4.43 g F / 1.87 g S = 2.37

There is a mass ratio of fluorine to sulfur of 3.51 to 1.

These results are consistent with the law of multiple proportions because the ratio of fluorine in the two compounds is 3:2.

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Answer:

Precentage error = 7.23%

Explanation:

The precentage error formula  is the  useful method  for determining precision of your experimental result

It can be calculated using :

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Precision means how close the experimental value to the true value or theoretical value

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vlabodo [156]
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nignag [31]

Answer:

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8 0
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