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Lynna [10]
3 years ago
11

Consider the reaction below to answer the following questions (4) a. The nucleophile in the reaction is _______ b. The Lewis aci

d catalyst in the reaction is ______ c. This reaction proceeds___________(faster or slower)
Chemistry
1 answer:
KATRIN_1 [288]3 years ago
5 0

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

a) Br^-

b) FeCl3

c) slower

d) see the first attached image

Explanation:

Aromatic compounds undergo electrophilic substitution sections in the presence of the appropriate electrophile.

In the reaction above, the Br^- nucleophile attacks the Lewis acid FeCl3. Recall that the nitro group is meta directing hence the incoming Br^+ electrophile is directed towards the meta position as shown in the image attached.

Note that the nitro group deactivates the ring towards electrophilic substitution hence the reaction is slower with nitrobenzene than with unsubstituted benzene.

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The sun produces energy by forming helium Its core
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Tomas takes a walk next to the ocean and finds a jellyfish that has washed ashore. Curious, he does some research about
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Answer:

The answer is absolutely D!

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That leaves you with your answer: D

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3 years ago
Electrolysis breaks down water to form hydrogen and oxygen gas. The word equation that represents this reaction is
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Hydrogen + oxygen 
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4 0
3 years ago
Read 2 more answers
Suppose that 1.15 g of rubbing alcohol (C3H8O) evaporates from a 65.0-g aluminum block. If the aluminum block is initially at 25
Naily [24]

Answer:

The final temperature is 10.2 °C

Explanation:

Step 1: Data given

Mass of C3H8O = 1.15 grams

Mass of an aluminium block = 65.0 grams

Initial temperature = 25.0 °C

Molar mass of C3H8O = 60.1 g/mol

Heat of vaporization of the alcohol at 25 °C is 45.4 kJ/mol

Specific heat of aluminium at 25°C = 0.900 J/g°C

Step 2: Calculate moles of C3H8O

Moles C3H8O = mass C3H8O / molar mass C3H8O

Moles C3H8O = 1.15 grams / 60.1 g/mol

Moles C3H8O = 0.0191 moles

Step 3: Calculate heat

Q = 45.4 kJ/mol * 0.0191 moles = 0.867 kJ = 867 Joules

Step 4: Calculate ΔT

Q = m*c*ΔT

⇒ Q = the heat transfer = 867 J

⇒ m = the mass of aluminium = 65.0 grams

⇒ c = the specific heat of aluminium = 0.900 J/g°C

⇒ ΔT = The change of temperature = TO BE DETERMINED

867 J =65.0 g *0.900 J/g°C * ΔT

ΔT = 867 / (0.900*65.0)

ΔT = 14.8

Step 5: Calculate the final temperature

ΔT = T2 - T1

14.8 = 25.0 - T1

T1 = 25.0 - 14.8

T1 = 10.2 °C

The final temperature is 10.2 °C

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