Question

Given the following data, determine the order of reaction with respect to H2.

Answer 1

Answer:

First-order with respect to hydrogen.

Explanation:

Hello!

In this case, considering that the rate law of this reaction can be expressed via:

$r=k*p_{H_2}^m*p_{ICl}^n$

If we want to know m, the order of reaction with respect to hydrogen, we need to relate the experiments 1 and 3 in order to get rid of the pressure of ICl:

$\frac{r_1}{r_3} =\frac{k*p_{H_2,1}^m*p_{ICl,1}^n}{k*p_{H_2,3}^m*p_{ICl,3}^n}$

Thus, we plug in the given rates, and pressures to get:

$\frac{1.34}{0.266} =\frac{k*250^m*325^n}{k*50^m*325^n}$

So we can cancel wout k and 325^n:

$\frac{1.34}{0.266} =\frac{250^m}{50^m}$

Next we solve for m, the order of reaction with respect to hydrogen:

$5.04 =5^m\\\\log(5.04)=m*log(5)\\\\m=\frac{log(5.04)}{log(5)} \\\\m=1.0$

It means it is first-order with respect to hydrogen.

Regards!