Ep= mgh
Ep = 40 x 9.8 x 10
Ep = 3920J
Ep = 3900J (2sf)
Answer:
final velocity = 9.6157 m/sec
Explanation:
To solve this question, we will use one of the equations of motion which is:
v^2 = u^2 + 2as
where:
v is the final velocity that we want to get
u is the initial velocity = 3.75 m/sec
a is the acceleration due to gravity = 9.8 m/sec^2
s is the distance = 4 m
Substitute with the givens in the equation to get the final velocity as follows:
v^2 = u^2 + 2as
v^2 = (3.75)^2 + 2(9.8)(4)
v^2 = 92.4625
v = 9.6157 m/sec
Hope this helps :)
Answer: Marie Curie's work with Becquerel made her more curious and prompted her to research and experiment with radioactivity.
Explanation:
Henri Becquerel was a French physicist who in 1896 discovered a new property of matter (which was later called <u>radioactivity</u>). This was accidentally observed when Becquerel found out that uranium salt was spontaneously emitting some kind of rays that went through different substances and were able to veil even a photographic film.
Then Marie Curie and her husband Pierre Curie carried out more experiments to study, in a <u>quantitative way</u>, the radiation emitted by the salts Becquerel studied <u>cualitatively,</u> and other salts that contained uranium. During this process they found other radioactive substances, such as: thorium, polonium and radium.
For that reason, the three of them were awarded the Nobel Prize in Physics in 1903 for their discovery of radioactivity.
A front is defined as a "boundary" that separates two masses of different air densities. I am not entirely sure, but I think the answers are either C or D, but I'm mostly convinced it's option D.
Answer:
The initial velocity of the gymnast is 8.5 m/s.
Explanation:
We can use the kinematic equation
![v_f^2= v_o^2+2ad](https://tex.z-dn.net/?f=v_f%5E2%3D%20v_o%5E2%2B2ad)
to figure out the initial velocity
of the gymnast.
Now, when the gymnast reaches the maximum height, the distance he has traveled is
, and his velocity is zero; therefore
.
Thus, we have
![0 = v_0^2+2(-10m/s^2)(3.6m)](https://tex.z-dn.net/?f=0%20%3D%20v_0%5E2%2B2%28-10m%2Fs%5E2%29%283.6m%29)
![v_0^2=72m^2/s^2](https://tex.z-dn.net/?f=v_0%5E2%3D72m%5E2%2Fs%5E2)
![\boxed{v_0= 8.5m/s}](https://tex.z-dn.net/?f=%5Cboxed%7Bv_0%3D%208.5m%2Fs%7D)