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ivann1987 [24]
3 years ago
14

What is the de Broglie wavelength for a proton (m = 1.67× 10^−27 kg) moving at a speed of 9.50 × 10^6 m/s? (h = 6.63 × 10^−34 J⋅

s)
Physics
1 answer:
SashulF [63]3 years ago
4 0

Answer:

De broglie wavelength = 4.17 pm

Explanation:

We have given mass of proton m=1.67\times 10^{-27}kg

Speed of proton v v=9.50\times 10^{6}m/sec

Plank's constant h=6.63\times 10^{-34}J-s

We have to find de broglie wavelength

De broglie wavelength is given by \lambda =\frac{h}{mv}=\frac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 9.5\times 10^6}=4.17\times 10^{-12}m=4.17pm

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