Answer:
Correct answer: V₂ = 1.79 m/s
Explanation:
Given:
m₁ = 32 kg the mass of the first student
V₁ = 2.4 m/s speed of the first student after pushing
m₂ = 43 kg the mass of the second student student
V₂ = ? speed of the second student after pushing
I₁ = m₁ · V₁ impulse of the first student
I₂ = m₂ · V₂ impulse of the second student
Under the law of impulse maintenance, the total impulse of an object must be constant over time.
Since the total impulse before pushing was equal to zero it must be afterwards.
I₁ + I₂ = 0 ⇒ I₂ = - I₁ ⇒ V₂ = - V₁
Given that the impulses are vectors a sign minus ahead of the first pulse mean, they are opposite directions.
m₂ · V₂ = m₁ · V₁ ⇒ V₂ = (m₁ · V₁) / m₂ = (32 · 2.4) / 43 = 1.79 m/s
V₂ = 1.79 m/s
God is with you!!!
The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.
<h3>What is resistance?</h3>
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)
The relation of resistance with length and thickness is given by ;
Hence, the resistance of tungsten wire will be 0.74 ohm.
To learn more about the resistance, refer to the link;
brainly.com/question/20708652
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Answer:
9 kg
Explanation:
Momentum is mass times velocity.
p = mv
36 kgm/s = m (4 m/s)
m = 9 kg