All categories

3 years ago

Which one is an example of kinetic energy

Physics

2 answers:

Jobisdone [24]3 years ago

6 0

None of the items on the list IS kinetic energy.

The rolling ball HAS kinetic energy.

allochka39001 [22]3 years ago

4 0

A is correct because kinetic energy is energy in motion. The ball is in motion rolling down the hill.

You might be interested in

How could you increase the kinetic thermal energy of a water

eduard

you can increase kinetic thermal energy of the water by boiling it.

5 0

3 years ago

Read 2 more answers

Please help me this is due today

Alex_Xolod [135]

Answer:

1) Acids have a sour taste.

Acid formulas start with "H", contain hydrogen and some react with active metals in a single replacement reaction to give off hydrogen gas.

An acid will turn blue litmus paper red

All acids are SOLUBLE in water.

Acids have a pH below 7.

2) Bases are bitter to taste a bitter taste is characteristic of all bases.

trong bases are very corrosive and can burn the skin.

Bases may or may not be soluble in water Bases that can dissolve in water are called alkalis

They can conduct electricity.

Bases lose their basicity when mixed with acids.

3) i dont know how to do it on here sorry but its self explanitory!!

4) 0-3 strongly

4-6 weakly

7 neutral

8-10 weakly

11-14 strongly

hydrochloric acid

lead acid battery

gastric acid

lemon juice

cola

vinegar

orange juice and apple juice

tomato juice

beer

tea or healthy skin

acid rain

coffee

urine

milk

healthy human saliva

pure water

blood

sea water

hand soap

household ammonia

bleach

house hold lye

Explanation:

4 0

3 years ago

What is needed to make alternative energy sources widely accepted?

svp [43]

i think what is needed is for people to see that alt. energy sources are very useful and inexpensive.

4 0

4 years ago

Briefly describe the difference between the amplitude of a wave (such as a light wave) and the frequency of light (again, such a

Mazyrski [523]

Answer:

a wave has a trough (lowest point) and a crest (highest point). The vertical distance between the tip of a crest and the wave’s central axis is known as its amplitude. This is the property associated with the brightness, or intensity, of the wave. The horizontal distance between two consecutive troughs or crests is known as the wavelength of the wave. Keep in mind that some waves (including electromagnetic waves) also oscillate in space, and therefore they are oscillating at a given position as time passes. The quantity known as the wave’s frequency refers to the number of full wavelengths that pass by a given point in space every second; the SI unit for frequency is Hertz (\text{Hz})(Hz)left parenthesis, start text, H, z, end text, right parenthesis, which is equivalent to “per seconds” \Big((left parenthesiswritten as \dfrac{1}{\text{s}} s

start fraction, 1, divided by, start text, s, end text, end fraction or \text{s}^{-1}\Big)s

−1

)start text, s, end text, start superscript, minus, 1, end superscript, right parenthesis. As you might imagine, wavelength and frequency are inversely proportional: that is, the shorter the wavelength, the higher the frequency, and vice versa. This relationship is given by the following equation:

c=\lambda \nuc=λνc, equals, lambda, \nu

where \lambdaλlambda (the Greek lambda) is the wavelength (in meters, \text{m}mstart text, m, end text) and \nuν\nu (the Greek nu) is the frequency (in Hertz, \text{Hz}Hzstart text, H, z, end text). Their product is the constant ccc, the speed of light, which is equal to 3.00\times10^8 \text{ m/s}3.00×10

m/s3, point, 00, times, 10, start superscript, 8, end superscript, start text, space, m, slash, s, end text. This relationship reflects an important fact: all electromagnetic radiation, regardless of wavelength or frequency, travels at the speed of light.

Explanation:

7 0

4 years ago

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket

NARA [144]

The constant acceleration of a rocket launched upward, calculated knowing that the time it takes for a bolt that falls off the side of the rocker was 6.30 seconds, is 5.68 m/s².

When the rocket is launched straight up with constant acceleration, the acceleration of the rocket is given by:

$v_{f_{r}} = v_{i_{r}} + at$

Where:

$v_{f_{r}}$ : is the final velocity of the rocket

$v_{i_{r}}$ : is the initial velocity of the rocket = 0

a: is the acceleration

t: is the time

After 4 seconds, the final speed of the rocket will be the initial speed of the bolt, so:

$v_{f_{r}} = v_{i_{b}} = at = 4a$

When the bolt falls off the side of the rocket, the bolt hits the ground 6.30 seconds later.

The initial height of the bolt will be the final height of the rocket, and vice-versa. With this, we can take the final height of the bolt as zero.

$y_{f_{b}} = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}$

$0 = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}$

$y_{i_{b}} = \frac{1}{2}9.81*(6.30)^{2} - 4a*6.30 = 194.7 - 25.2a$

Now, as we said above, this height (of the bolt) will be the final height of the rocket, so:

$y_{f_{r}} = y_{i_{r}} + v_{i_{r}}t - \frac{1}{2}gt^{2}$

$194.7 - 25.2a = 0 + 0 - \frac{1}{2}a(4)^{2}$

$a = \frac{194.7}{33.2} = 5.86 m/s^{2}$

Therefore, the acceleration of the rocket is 5.68 m/s².

You can find another example of acceleration calculation here: brainly.com/question/24589208?referrer=searchResults

I hope it helps you!

3 0

3 years ago