Answer:
<em>In the observational method, the hypothesis is constructed to explain the observations. A simple one may be a generalization of the observations. A more complex hypothesis may postulate a relationship between the events, and may even be used to predict other observations.</em>
Answer:
They both describe atoms as being made up of positive and negative matter.
Explanation:
In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:
- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere
- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.
Answer:
x₁ = 0.1878 m
Explanation:
For this exercise we will use conservation of energy
starting point. Highest point
Em₀ = U = m g h
final point. Lowest point with fully compressed spring
Em_f = K_e + U
Em_f = ½ K x² + m g x
energy is conserved
Em₀ = Em_f
m g h = ½ K x² + m g x
½ K x² + mg (x- h) = 0
let's substitute
½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0
3.65 x² + 0.294 (x- 0.25) = 0
x² + 0.080548 (x- 0.25) = 0
x² - 0.020137 + 0.080548 x = 0
x² + 0.080548 x - 0.020137 = 0
let's solve the quadratic equation
x = [0.080548 ±√ (0.080548² + 4 0.020137)] / 2
x = [0.080548 ± 0.29502] / 2
x₁ = 0.1878 m
x₂ = -0.1072 m
These are the compression and extension displacement of the spring
Answer:
The bus moved after our girl Sandy passed out = S = 905.04 m
Explanation:
At t = 0 sec Vi = 80mph = 35.76 m/s
t = 30 sec Vf = 55mph = 24.58 m/s
According to the first equation of motion
<u>Vf = Vi + at</u>
24.587 = 35.76 + a(30)
a = - 0.373 m/s2 (negative sign shows deceleration)
Now for distance travelled in 30 sec we have
second equation of motion
<u> S=Vit+1/2at2</u>
S = 35.76 x 30 + 1/2 x -0.373 x 30 x 30
S = 905.04 m
Answer:
True
Explanation:
Electronegativity difference of less than 0.4 characterized covalent bonds. For two atoms with an electronegativity difference of between 0.4 and 2.0, a polar covalent bond is formed-one that is neither ionic nor totally covalent.