All categories

3 years ago

How many molecules of C2H4Cl2 can be prepared from 15 C2H4 molecules and 8Cl2 molecules?

Chemistry

1 answer:

Travka [436]3 years ago

7 0

Answer:

8 molecules of C₂H₄Cl₂

Explanation:

Molecules of C₂H₄ = 15 molecule

Molecules of Cl₂ = 8 molecules

Molecules of C₂H₄Cl₂ =?

First of all we will write the balance chemical equation,

C₂H₄ + Cl₂ → C₂H₄Cl₂

we are given 8 molecules of Cl₂ and 15 molecules of C₂H₄, which means that 8 molecules of chlorine react with 8 molecules of C₂H₄ and will limit the reaction product. The seven molecules of C₂H₄ will remain unreactive. So , the chlorine will be the limiting reactant.

8 molecules of Cl₂ × 1 mole of C₂H₄Cl₂/ 1 mole of Cl₂

8 molecules of C₂H₄Cl₂

You might be interested in

To study a key fuel-cell reaction, a chemical engineer has 20.0-L tanks of H₂ and of O₂ and wants to use up both tanks to form 2

Lapatulllka [165]

the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Given , to study a key fuel-cell reaction , a chemical engineer has 20.0L tanks of H2 and O2 and wants to use up both tanks to form 28.0mol of water at 23.8°C .

the reaction of the fuel cell is given by ,

H2(g) +1/2 O2 ( g) →H2O

Moles of H2 required = 28 mol

moles of O2 required = 14mol

Now according to van der waals equation ,

p= (nRT/ V-nb) - an^2 / V^2

for H2 , a = 0.2453L^2bar /mol^2 , b= 0.02651L/mol

P for H2

= (28×0.0821×296.8/20-28×0.02651 ) -(0.2456 ×28×28/20×20)

P for H2 = 35.4291079-0.481376 = 34.9477319 atm

for O2 , a = 1.38L^2bar/mol^2 , b = 0.03186L/mol

P for O2 = (14×0.0821×296.8 /20-14×0.03186) - (1.382×14×14/20×20)

P for O2 = 17.4461807 - 0.67718 =16.7690007 atm

Hence , the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Learn more about pressure here :

brainly.com/question/25965960

#SPJ4

6 0

1 year ago

In a titration experiment, hcl and lioh solutions were used. the initial volume of hcl was 1.25ml and lioh was 2.65 ml. the fina

aliya0001 [1]

Answer is: <span>the molarity of HCl is </span>0.097 M.
Chemical reaction: LiOH + HCl → LiCl + H₂O.
V(HCl) = 13.60 mL - 1.25 mL = 12.35 mL.
V(LiOH) = 11.20 mL - 2.65 mL = 8.55 mL.
c(LiOH) = 0.140 M.
From chemical reaction: n(LiOH) : n(HCl) = 1 : 1.
c(HCl) · V(HCl) = c(LiOH) · V(LiOH).
c(HCl) = 8.55 mL · 0.140 M / 12.35 mL.
c(LiOH) = 0.097 M.

8 0

3 years ago

The end point of a titration was reached after 22 ml of 0.050 m disodium edta titrant was dispensed into a solution containing t

ale4655 [162]

The moles of disodium edta used is calculated using the below formula

moles =molarity x volume in liters

molarity=0.050m
volume in liters = 22/1000=0.022 L

moles is therefore= 0.022 x0.050 =1.1 x10^-3 moles of disodium edta

4 0

3 years ago

Read 2 more answers

I've asked before and gotten spammed hopefully I won't get spammed this time please help me with this someone. pls help anyonw

elena55 [62]

Answer:

See below!

Explanation:

A. The picture of the graph is attached. You can tell the amount of protons in an element by looking at the periodic table. The elements are ordered by the number of protons in an element.

B. Carbon and silicon are at the peaks of the chart. The peak is the highest point in a graph.

C. The elements belong to the non-metal group.

D. The halogens are non-metals, and their vapors are colorless.

The halogens are toxic to humans.

Halogen molecules are made of two atoms; they are diatomic.

Halogens react with non-metals to form crystalline compounds that are salts.

The halogens get less reactive going down the group on the periodic table.

Halogens can bleach vegetable dyes and kill bacteria.

E. The picture of the table is attached. To figure which numbers to put where, you need to pay attention to the other numbers. The halogens follow a trend with each of these properties. You have to put in the numbers that fit in among the other numbers.

3 0

3 years ago

How might the biodiversity of a mowed lawn compare to that of huge weedy field?

Dennis_Churaev [7]

Answer: The mowed lawn is the one from where the grasses are removed by using the machines or tools.

Explanation:

The mowed lawn is expected to have low number of species as the grasses may be few or scanty thus can support the population of few species like insects, mice, birds, and small number of grazing animals. On the other hand the weedy field can be hub of insects, reptiles like snakes, small mammals, and large mammals. Large weed field can provide food, and habitat to the large number of species. This will support the increase in biodiversity as compared to the mowed lawn.

5 0

2 years ago