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larisa [96]
3 years ago
13

One hundred grams of radium are stored in a container. The amount RR (in grams) of radium present after tt years can be modeled

by R=100e−0.00043tR=100e−0.00043t. After how many years will only 5 grams of radium be present? Round your answer to the nearest whole year.
Mathematics
1 answer:
Alona [7]3 years ago
5 0
Ending Amount = Beginning Amount * e^k*t
5 grams = 100 grams * e^-.00043 * years

We have to solve the equation for "years"
(You can find the formula here: http://www.1728.org/halflif2.htm
or you can just read the next line

time = natural log (bgng amt / endg amt) / k
time = natural log (100 / 5) / .00043
time = natural log (20) / .00043
time = 2.9957322736 / .00043
time =  <span> <span> <span> 6,967</span></span></span><span> years
</span>
We should double-check this.
First, we need the half-life
k = ln(.5) / half-life
half-life = <span>-.693147 / -.00043
half-life = 1,612 years
Now let's see how many half-lives that is:
</span><span>6,967 / 1,612 years = 4.2 half-lives
So basically, after 4 half-lives the mass should go from

100
50  1 half life
25</span><span><span>  2 half lives</span>
12.5 </span><span>3 half lives
</span> 6.25 <span>4 half lives</span>

6.25 is very close to 5 grams so we can assume we have calculated correctly.


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