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Oksi-84 [34.3K]
3 years ago
5

What is the density of an object with a mass of 57.8g and a volume of 112.4mL?

Chemistry
1 answer:
Elina [12.6K]3 years ago
7 0

Answer:

D=m/v

D=57.8/112.4

D=0.51423487544 g/mL^2

Explanation:

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Which is an example of a chemical reaction
valkas [14]

Answer:iron and oxygen combining to make rust. vinegar and baking soda combining to make sodium acetate, carbon dioxide and water

Explanation:

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3 years ago
The particles of a gas are<br> O electrons<br> O atoms or molecules<br> O neutrons<br> O waves
Harrizon [31]
Answer:
atoms or molecules

Explanation:
Gas particles are constantly bumping into each other and the borders of their container.

8 0
2 years ago
A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?
Lunna [17]

Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L

7 0
3 years ago
Will an object with a density of 0.999 sink or float
Semmy [17]

The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.

7 0
3 years ago
Consider the reaction of Mg3N2 with H2O to form Mg(OH)2 and NH3. If 4.33 g H2O is reacted with excess Mg3N2 and 6.26 g of Mg(OH)
Len [333]

Answer:

89.34%

Explanation:

First, write a balanced reaction.

Mg3N2 + <u>6</u>H2O --> <u>3</u>Mg (OH)2 + <u>2</u>NH3

Next determine the moles of the known substance, or limiting reagent ( H2O)

n= m/MM

n ( H2O) = 4.33/(1.008×2)+16

n(H2O)= 0.2403

Use the mole ratio to find the moles of Mg(OH)2

0.2403 ÷2

n (Mg (OH)2) = 0.1202

Next, find the theoretical mass of Mg (OH)2 that should have been produced

m= n × MM

m= 0.1202 × (24.305 + (16×2) +(1.008 ×2))

=7.007g

To find percentage yield, divide the experimental amount by the theoretical amount and multiply by 100.

6.26/ 7.007 × 100

=89.34%

7 0
3 years ago
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