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3 years ago

A. make an argument for halting the advances of technology? b. make an argument for continuing advances in technology

1 answer:

6 0

Halting advances in tech could be useful because the automation in many tasks has rendered the human touch obsolete in many lower-level positions. They can be done by machines without the need for stoppage time for breaks. Continuing technology can be useful because it can increase output and make it easier for people to get what they're wanting or needing without spending extravagant amounts of resources.

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WOULUJUTUL RECIPECUIUS.

3241004551 [841]

The force between the two objects is 19.73 nN.

Explanation:

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider $M_{1}$ and $M_{2}$ as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

$\text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}$

As gravitational constant $G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}$ , $M_{1}$ = 20 kg and $M_{2}$ = 100 kg, while d = 2.6 m, then

$\text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}$

Thus, we get finally,

$\text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}$

As we know, nano denoted by letter 'n' equals to $10^{-9}$

So the force acting between two objects is 19.73 nN.

7 0

3 years ago

What is static and sliding friction

vodka [1.7K]

Static friction is the friction that exists between a stationary object and the surface on which it's resting.
frictional force occurs when you try to push an object alongside a surface.

5 0

3 years ago

What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?

sveta [45]

Momentum = (mv).
(2110 x 24) = 50,640kg/m/sec. truck momentum. 
Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec

8 0

3 years ago

In 5 meters, a person running at 0.8 m/s accelerates at 1.6 m/s2. How fast 16 points

frutty [35]

They were going at a velocity 4.07m/s

Explanation:

Distance s =5 m

initial velocity u= 0.8 m/s

Acceleration a =1.6m/s2

We have to calculate the velocity with which they were going afterwards i.e final velocity.

Use the equation of motion

$v^2=u^2+2as\\=0.8^2+2\times 1.6\times 5\\=16.64\\v=4.07 m/s$

They were going with a velocity 4.07 m/s afterwards.

5 0

3 years ago

During an experiment, you take a measurement of 12.9 inches.

svlad2 [7]

Answer:

1 inch = 2.54 cm

12.9 inches= 12.9 x 2.54

= 32.766

= 32.8 cm (approximately)

Hope it helps...

7 0

3 years ago