Answer:
the actual specific work required by the compressor to operate is 2425.88 kJ/kg
Explanation:
Given that;
h₁ = 1350 kJ/kg
h₂₅ = 3412 kJ/kg
compressor efficiency П_ise = 0.85
we know that;
compressor efficiency П_ise = isentropic work / actual work
П_ise = (h₂₅ - h₁) / (h₂ - h₁ )
so
0.85 = (h₂₅ - h₁) / (actual work )
Actual work = (h₂₅ - h₁) / 0.85
Actual work = (3412 - 1350) / 0.85
Actual work = 2062 / 0.85
Actual work = 2425.88 kJ/kg
Therefore the actual specific work required by the compressor to operate is 2425.88 kJ/kg
The correct answer is An abrasive wheel.
Answer:
The p-n junction is a region formed when a p -type semiconductor material is joined to an n-type semiconductor material
Explanation:
The p type semiconductor has holes as its majority charge carriers making it positively charged while the n –types has an overall negative charge. At the junction the holes move towards the electron until such a time when there is a balance in charges from both materials, which leads to the formation of the depletion zone as shown in the attachment below
Because of the skin depth effect, the current at high frequency tends to flow at very low depth from radius. Then at high frequency the effective cross section of the wire is narrower than at DC.
Fro example skin depth at 100 kHz is 0.206 mm (0.008”), a wire more thicker than AWG26 could be a waste of copper, better use a bunch of thin wire (Litz wire) to rise the Q factor.
Answer:
88.18 W
Explanation:
The weight of the boy is given as 108 lb
Change to kg =108*0.453592= 48.988 kg = 49 kg
The slope is given as 6% , change it to degrees as
6/100 =0.06
tan⁻(0.06)= 3.43°
The boy is travelling at a constant speed up the slope = 7mi/hr
Change 7 mi/h to m/s
7*0.44704 =3.13 m/s
Formula for power P=F*v where
P=power output
F=force
v=velocity
Finding force
F=m*g*sin 3.43°
F=49*9.81*sin 3.43° =28.17
Finding the power out
P=28.17*3.13 =88.18 W
