Answer:
mass = 9.7 kg
Explanation:
As we know that when object is at rest on the ground of flat base then we will have
so from here
now we have
N = 95 Newton
now from above equation we will have
Velocity = Frequency x Wavelength
= 18 x 13 = 234 mm/s
Answer:
The velocity of Mosquito with respect to earth will be 0.302m/s
Explanation:
V(ma) = 1.10 m/s, east Velocity of mosquito with respect to air
V(ae) = 1.4 m/s at 35° Velocity of air with respect to Earth in west of south direction.
Velocity of Mosquito with respect to earth will be
V(me) = V(ma) + V(ae)
We need to find the mosquito’s speed with respect to Earth in the x direction.
V(x, me) = V(x, ma) + V(x, ae) = V(ma) + V(ae)(cos theta(ae) )
Angle (ae) = –90.0° − 35°=−125°
V(x, me) = 1.10 + (1.4)Cos(-125)
= 1.10 + 1.4(-0.57)
= 1.10 -0.798
= 0.302
So the velocity of Mosquito with respect to earth will be 0.302m/s
Potential energy = (mass) · (gravity) · (height)
PE = (60 kg) · (9.8 m/s²) · (10 m)
PE = (60 · 9.8 · 10) · (kg · m²/s² )
PE = 5,880 joules
