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Arlecino [84]
3 years ago
7

Sand is made of tiny pieces of rock that have been worn down by wind and water. Explain why the formation of sand is a physical

change.
Physics
2 answers:
Sliva [168]3 years ago
8 0

The formation of sand is a physical change because some of the physical properties of the rocks change, but their identities do not. The particles of rock are rearranged as their sizes and shapes change, but their identities and total mass remain the same.

katovenus [111]3 years ago
8 0

The formation of sand is a physical change because some of the physical properties of the rocks change, but their identities do not. The particles of rock are rearranged as their sizes and shapes change, but their identities and total mass remain the same.



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Tracy scuffs her socked feet across a carpet. When she touches a doorknob, she gets a small shock. How did Tracy become charged?
densk [106]
<span>through friction between her feet and the carpet </span>
5 0
4 years ago
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Calculate the force of earth's gravity on a 1kg mass at earth's surface. the mass of the earth is 6.0
jonny [76]

Force of earth gravity on 1 kg mass is 9.8 N.

Since the mass is at earth surface, therefore its distance from the centre of earth is equal to the radius of the earth i.e. 6400 km.

The force of earth gravity is calculated as

F=GMm/r^2 =(6.67*〖10〗^(-11)*6*〖10〗^24*1)/〖(64*〖10〗^6)〗^2 =9.8 N

4 0
3 years ago
A cyclist has a momentum of 771.9 kg m/s. if her mass is 93 kg what is the speed of the cyclist?
MrMuchimi
Take 771.9 Kg M/s  because that's how fast she is moving and divide it by 93 kg because that is her force pushing down

771.9/93= 8.3

Answer: A. 8.3 M/s

P.s I changed my answer on the last question you asked so change that.
3 0
4 years ago
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A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg
Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

E_i=\frac{1}{2}mv^2

Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0
3 years ago
A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?
lubasha [3.4K]

The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

<h3>How to find the net force on the box?</h3>
  • Let us draw the free body diagram of the given box with the data's given in the question.
  • From the diagram, we get,

                                 N=mg\\F_t=ma\\F_t=F-f

where, N is the normal reaction, mg is the weight of the box, F_t is the net force, f is the kinetic friction.

  • We have the expression for kinetic friction as,

                      f=kN=kmg=0.267*1.75*9.8= 4.58N

  • Thus, the net force will be,

                        F_t= 8.35-4.58=3.77N

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

Learn more about the basic forces on a body here:

brainly.com/question/28061293

#SPJ1

8 0
2 years ago
Read 2 more answers
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