A plane was traveling at a constant speed of 250 m/s in a straight line for 50min. What is the plane’s acceleration ?

On Earth, the gravitational Field strength is much than on the moon. If a piece of rock was taken from the Moon to the Earth, st

nikklg [1K]

Ok so I’m pretty sure the answer would be 2 because the mass of the rock would have the same mass on Earth as it has on the moon. Also the Density of a solid object remains constant meaning it doesn’t change. But the weight would change because the Earths gravitational pull is more than that of the moon. I hope this helped!

7 0

3 years ago

А<br> is a push or pull.

guajiro [1.7K]

Answer:

A

Explanation:

ignore this on...............................

7 0

3 years ago

Let A^=6i^+4j^_2k^ and B= 2i^_2j^+3k^. find the sum and difference of A and B

andreyandreev [35.5K]

Explanation:

Let $\textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}}$ and $\textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}$

The sum of the two vectors is

$\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}$

$= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}$

The difference between the two vectors can be written as

$\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}$

$= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}$

8 0

3 years ago

Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl

kherson [118]

Answer:

0.04455 Hz

Explanation:

Parameters given:

Wavelength, λ = 6.5km = 6500m

Distance travelled by the wave, x = 8830km = 8830000m

Time taken, t = 8.47hours = 8.47 * 3600 = 30492 secs

First, we find the speed of the wave:

Speed, v = distance/time = x/t

v = 8830000/30492 = 289.58 m/s

Frequency, f, is given as velocity divided by wavelength:

f = v/λ

f = 289.58/6500

f = 0.04455 Hz

8 0

3 years ago

Which of the following represents a possible magnitude for the force of static friction when Xavier applied 72.1 Newtons of forc

lana66690 [7]

The possible magnitude for the force of static friction on the stationary cart is 72.1 N.

The given parameters:

<em>Applied force on the cart, F = 72.1 N</em>

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Based on Newton's second law of motion, the force applied to object is directly proportional to the product of mass and acceleration of the object.

F = ma

Static frictional force is the force resisting the motion of an object at rest.

$\Sigma F = 0\\\\F -F_f = 0$

where;

$F_f$ is the frictional force

$F= F_f \\\\72.1 = F_f\\\\F_f = 72.1\ N$

Thus, the possible magnitude for the force of static friction on the stationary cart is 72.1 N.

Learn more about Newton's second law of motion: brainly.com/question/25307325

8 0

2 years ago