Question

Calculate the period of a ball tied to a string of length 0.468 m making 3.8 revolutions every second. Answer in units of s. Your answer must be within ± 2.0%

Answer 1

Answer:

0.26315 s

Explanation:

The frequency of the ball tied to a string system is 3.8 rev/s.

That means in one second the ball will complete 3.8 revolutions.

The time period will be the reciprocal of this frequency

$T=\dfrac{1}{f}\\\Rightarrow T=\dfrac{1}{3.8}\\\Rightarrow T=0.26315\ s$

The time period is 0.26315 s

It can be also solved in the following way

$1\ s=3.8\ rev\\\Rightarrow 1\ rev=\dfrac{1}{3.8}\ s\\\Rightarrow 1\ rev=0.26315\ s$

The time period is 0.26315 s