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Whitepunk [10]
2 years ago
15

Which term describes the number of joules used per second by a circuit?

Physics
2 answers:
jasenka [17]2 years ago
5 0

Answer:

B) Power

Explanation:

The power is defined by the following equation:

P = W / t

where:

W = work = Force * Distance = [Newton] * [meter]

t = time = seconds

The units for work are give en Newton per second, which is equal to Joules

And for power the unit used commonly is Watts, therefore:

Watts = (Joule/second)

seropon [69]2 years ago
4 0

Answer:

power

i hope this helped :)

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The concept of this question can be well understood by listing out the parameters given.

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The purpose is to determine the spring constant.

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\mathsf{S = ut + \dfrac{1}{2}gt^2}

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∴

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\mathsf{0.3 =4.9*(t^2)}

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By applying the equation of the time period of a simple harmonic motion.

\mathsf{T = 2 \pi \sqrt{\dfrac{m}{k}}}

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\mathsf{t = \dfrac{T}{2}}

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\mathsf{T = 2 \pi \sqrt{\dfrac{m}{k}}}

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\mathsf{\dfrac{T}{2 \pi } = \sqrt{ \dfrac{m}{k}}}

\Big(\dfrac{T}{2 \pi }\Big)^2 = { \dfrac{m}{k}

\dfrac{T^2}{(2 \pi)^2 }= { \dfrac{m}{k}

\mathsf{ T^2 *k = 2 \pi^2*m} \\ \\  \mathsf{  k = \dfrac{2 \pi^2*m}{T^2}}

\mathsf{  k =\Big( \dfrac{(2 \pi)^2*(51 \times 10^{-3})}{(0.494)^2} \Big) N/m}

\mathbf{  k =8.25 \ N/m}

Therefore, we conclude that the spring constant as a result of instantaneous rest caused by the compression of the spring is 8.25 N/m.

Learn more about simple harmonic motion here:

brainly.com/question/17315536?referrer=searchResults

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