Two oxide of sulphur,A and B were analyzed and the results obtained showed that in oxide A,3.50g of sulphur combined with 6.00g
1 answer:
Answer:
See Explanaton
Explanation:
The law of multiple proportions states that when two same elements form more than a compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers.
<u>Oxide A</u>
3.50g of sulphur combined with 6.00g of oxygen
Oxygen:Sulphur = 6 : 3.5
<u>Oxide B</u>
2.80g of sulphur combined with 9.55g
Oxygen : Sulphur = 9.55 : 2.8
Therefore:
The ratio of Oxygen to Sulphur in Oxides A and B is:
Ratio of Oxygen=1:2
There is exactly twice in Oxide B as in Oxide A.
This result illustrates the law of multiple proportions.
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Answer: -
15.55 M
35.325 molal
Explanation: -
Let the volume of the solution be 1000 mL.
Density of nitric acid = 1.42 g/ mL
Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid
= 1000 mL x 1.42 g/ mL
= 1420 g.
Percentage of HNO₃ = 69%
Amount of HNO₃ =
= 979.8 g
Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol
Number of moles of HNO₃ =
= 15.55 mol
Molarity is defined as number of moles per 1000 mL
We had taken 1000 mL as volume and found it to contain 15.55 moles.
Molarity of HNO₃ = 15.55 M
Mass of water = Total mass of nitric acid solution - mass of nitric acid
= 1420 - 979.8
= 440.2 g
So we see that 440.2 g of water contains 15.55 moles of HNO₃
Molality is defined as number of moles of HNO₃ present per 1000 g of water.
Molality of HNO₃ =
= 35.325 molal
Explanation:
According to the Beer-lambert' s law,
Absrobance = absrobptitvity × lenght × concentration
So, if we will plot a graph between absrobance and concentration then we will obtain a straight line
Hence, formula to calculate slope of the graph is as follows.
The slope of graph =
The given data is as follows.
= 0.412 (first point)
= 0.642 (second point)
= 0.240 ppm (first point)
= 0.475 ppm (second point)
Hence, putting these values into the above formula we will calculate the value of slope as follows.
Slope =
=
=
= 0.978
It is known that for the graph, line equation can be written as follows.
y = mx + c ........... (1)
where, C = intercept
m = slope
Hence, calculate the value of intercept as follows.
0.412 = + c
c = 0.178
As it is given that the absorbance values 0.454 (the y-axis value). Therefore, putting this value into equation (1) we get the following.
y = mx + c
0.454 = + 0.178
0.276 = 0.978x
x = 0.282 ppm
Thus, we can conclude that the concentration of Pb in the given sample is 0.282 ppm.