Increased air temperatures decrease the salinity of the ocean since more ice is melting adding more fresh water to the oceans, therefore slowing down the great ocean conveyor belt.
<h3>What is an ocean conveyor belt?</h3>
Ocean conveyor belt system in which water moves between the cold depths and warm surface in oceans throughout the world.
Increases in temperatures of surrounding entities like ice and an increase in precipitation adds fresh water into the sea, which lower salinity. Seawater with lower salinity is lighter in density and won't sink as much as denser water.
As the seawater gets saltier, its density increases, and it starts to sink. Surface water is pulled in to replace the sinking water, which in turn eventually becomes cold and salty enough to sink. This initiates the deep-ocean currents driving the global conveyer belt.
Hence, option A is correct.
Learn more about the conveyor belt here:
brainly.com/question/3044640
#SPJ1
Explanation:
magnetization
coz it will still have two pols that is north and south pole
Answer:
3-chloro propan-1-ol
Explanation:
As long as you're writing IUPAC name of a compound, you must mark that the sequence of carbon atoms in the chain from alpha-carbon, which is the carbon right next to the -OH group in this case
Answer:
The answer to your question is 330 g of CHO
Explanation:
Data
Calories needed = 2200 kcal/day
CHO = 60%
Proteins = 15%
Fats = 25%
Grams of carbohydrates needed = ?
Process
1.- Calculate the number of calories in 60% of 2200 kcal
2200 kcal ---------------- 100%
x --------------- 60%
x = (60 x 2200) / 100
x = 1320 kcal
2.- Calculate the grams of CHO
1 g of CHO ---------------- 4 kcal
x ---------------- 1320 kcal
x = (1320 x 1) / 4
x = 1320/4
x = 330 g of CHO
The theoretical yield of Carbon dioxide : 0.544 g
<h3>Further explanation</h3>
Given
0.64 g Methane
1.1 g Oxygen gas
Required
The theoretical yield of Carbon dioxide
Solution
Reaction
CH₄ + 2O₂ → CO₂ + 2H₂O.
Find limiting reactant(mol : coefficient)
= mass : MW
= 0.64 : 16
= 0.04
mol : coefficient = 0.04 : 1 = 0.04
= mass : MW
= 1.1 : 32
= 0.034
mol : coefficient = 0.034 : 2 = 0.017
O₂ as a limiting reactant(smaller)
Mol CO₂ based on mol O₂
From equation, mol ratio CO₂ : O₂ = 1 : 2 , so mol CO₂ :
= 1/2 x mol O₂
= 1/2 x 0.034
= 0.017
Mass O₂ :
= 0.017 x 32 g/mol
= 0.544 g