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3 years ago

Which of the following statements about oudlear energy stre?

Chemistry

1 answer:

Alborosie3 years ago

6 0

Answer:

Explanation:

i got it right on plato

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A party balloon contains 5.50 x 10 ^22 atoms of helium gas. What is the mass, in grams of the

eduard

Answer:

$\boxed {\boxed {\sf A. \ 0.365 \ g\ He}}$

Explanation:

1. Convert Atoms to Moles

We must use Avogadro's Number: 6.022*10²³. This is the number of particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, the particles are atoms of helium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}$

Multiply by the given number of helium atoms.

$5.50 *10^{22} \ atoms \ He *\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}$

Flip the fraction so the atoms of helium cancel.

$5.50 *10^{22} \ atoms \ He *\frac {1 \ mol \ He}{6.022*10^{23} \ atoms \ He}$

$5.50 *10^{22} *\frac {1 \ mol \ He}{6.022*10^{23} }$

$\frac {5.50 *10^{22} \ mol \ He}{6.022*10^{23} }= 0.09133178346 \ mol \ He$

2. Convert Moles to Grams

We must use the molar mass, which is found on the Periodic Table.

Helium (He): 4.00 g/mol

Use this as a ratio.

$\frac { 4.00 \ g \ He }{ 1 \ mol \ He}$

Multiply by the number of moles we calculated. The moles will then cancel.

$0.09133178346 \ mol \ He *\frac { 4.00 \ g \ He }{ 1 \ mol \ He}$

$0.09133178346*\frac { 4.00 \ g \ He }{ 1 }$

$0.3653271338 \ g\ He$

3. Round

The original measurement has 3 significant figures (5, 5, and 0). Our answer must have the same. For the number we calculated, it is thousandth place. The 3 in the ten thousandth place tells us to leave the 5.

$0.365 \ g\ He$

The mass is 0.365 grams of helium so choice A is correct.

7 0

3 years ago

The rate constant for a first-order reaction is 2.4 x 10-4 L/(mol's) at 600 K and 6.2 x 10-4L/(mol · s) at 900 K.

Alika [10]

Answer:

(R = 8.31 J/(mol · K)) 0.88 × 104 J/mol 1.42 × 102 J/mol 1.42 × 104 J/mol at 600 K and 6.2 × 10-4 L/(mol · s) at 900 K. Calculate the activation energy.

6 0

3 years ago

Please please please help me ill give brainliest

Mnenie [13.5K]

Answer: the answer is A.

8 0

3 years ago

if the pressure of a gas at constant volume is 3.5 atm at 100°c, what will the pressure be if the tempature is changed to 250°c?

Degger [83]

Sorry don't know this one

6 0

3 years ago

15 POINTS PLS HELP!!!!!

scZoUnD [109]

Answer: (C) Vaporizing

Explanation:

Vaporization is the process in which the substance change the state of of liquid into the gas state.

The vaporization process require the largest input of the energy as when the state is in the solid state then, the solid substances contain the strong forces of the attraction and they require high energy to break these strong bonds.

For changing the liquid state into the gases state we require to overcome the surface tension and require enough energy for acquiring the vaporization state.

Therefore, option (C) is correct.

5 0

3 years ago