We can begin with the following formula for the resistance of a wire:
We assume that resistivity
of both wires is the same. So they differ in length
and cross-sectional area
.
We assume that both wires are perfect cylinders, which means that their cross section is given by the following formula:
.
Where r is the radius of a wire. Diameter is just 2*r.
With all of this information, we can write equations for the resistance of both wires and then just divide them to find the ratio.
For wire 2 we have:
For cross section A, we write
, because if the diameter of wire two is twice as big that means it's radius is twice as big. Keep in mind we are only interested in ratios here.
For wire 1 we write:
.
When we divide those two equations we get:
Answer:
Explanation:
d = v * t, where d is the distance and v is the velocity, t is the time
cheetah
v = 95.4 km/h
gazelle
v= 74.4 km/h
d1 = 83m = 0.083 km
when the cheetah catches the gazelle the distances will be equal
95.4t= 74.4t+0.083
t= 0.00395 h* (3600s/1h) = 14.22 s
Search Results<span>By simply wrapping wire that has an electrical current running through it around a nail, you can make an electromagnet. When the electric current moves through a wire, it makes a magnetic field. ... You can make a temporary magnet by stroking apiece of iron or steel (such as a needle) along with a permanent magnet.
Hope This Helps!</span>
I’ll explain this to you draw a diagram of seismometer show how the earth moves it’s round and it moves on it axis and spins fully which takes it a year 365 days
Answer:
E₂ / E₁ = 521.64 / 5.95 =87.67
Explanation:
Let d be the distance covered inside electric field . Lt q be the magnitude of charge.
Force under field E₁ = q E₁
acceleration = qE₁/ m
d = 1/2 a t²
d = .5 ( qE₁ / m) x 32.3²
d = 521.64 ( qE₁ / m)
Similarly for return journey,
d = .5 x ( qE₂ / m) x 3.45²
d = 5.95x( qE₂ / m)
521.64 ( qE₁ / m) = 5.95x( qE₂ / m)
E₂ / E₁ = 521.64 / 5.95 =87.67