Tc-99m<span> is a </span>metastable isomer<span> of </span>Tc-99. It finds widespread applications in <span>medical diagnostic procedures.
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Tc-99 is also a radioactive element. It's half-life is 2,11,000 years. Upon radioactive decay, it emits beta particles and gets converted into stable compound Ruthenium-99
This process of radioactive decay is shown below.
99 43Tc → 99 44Ru + 0 -1e
(stable) (β particle)
<h2>Input =
![NADP^+](https://tex.z-dn.net/?f=NADP%5E%2B)
, water and Output =
![NADPH + O_2](https://tex.z-dn.net/?f=NADPH%20%2B%20O_2)
</h2>
Explanation:
The light reactions of photosynthesis use water and produce Oxygen, NADPH.
The equation for photosynthesis :
→ ![C_6H_12O_6 + 6 O_2](https://tex.z-dn.net/?f=C_6H_12O_6%20%2B%206%20O_2)
The process of photosynthesis in two stages -
- The first stage is called the light reaction in which the light energy from the sun is captured and converted into chemical energy stored in the form of ATP and NADPH
- The second stage is the process of conversion of ATP molecules to sugar or glucose (the Calvin Cycle)
For a light reaction -
Net Input is of,
, ![Light, Water, ADP](https://tex.z-dn.net/?f=Light%2C%20Water%2C%20ADP)
Net Output is of, ![ATP, NADPH, O_2](https://tex.z-dn.net/?f=ATP%2C%20NADPH%2C%20O_2)
Answer:
<em>(H30+)= 1x10^-6 M</em>
Explanation:
Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:
1x 10-8 mol/L equals to1x10-8 M
(H3O+) x (OH-) = 1x10^-14
(H30+)x 1x 10^-8 =1x10^-14
(H30+)= 1x10^-14/1x 10^-8
<em>(H30+)= 1x10^-6 M</em>
Answer:
10.64
Explanation:
Let's consider the basic reaction of cyclohexamine, C₆H₁₁NH₂.
C₆H₁₁NH₂(aq) + H₂O(l) ⇄ C₆H₁₁NH₃⁺(aq) + OH⁻ pKb = 3.36
C₆H₁₁NH₃⁺ is its conjugate acid, since it donates H⁺ to form C₆H₁₁NH₂. C₆H₁₁NH₃⁺ acid reaction is as follows:
C₆H₁₁NH₃⁺(aq) + H₂O(l) ⇄ C₆H₁₁NH₂(aq) + H₃O⁺(aq) pKa
We can find the pKa of C₆H₁₁NH₃⁺ using the following expression.
pKa + pKb = 14.00
pKa = 14.00 - pKb = 14.00 - 3.36 = 10.64