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GuDViN [60]
4 years ago
8

One element of the circulatory system is the __________.

Chemistry
2 answers:
Verizon [17]4 years ago
6 0

Answer:

heart

Explanation:

IrinaK [193]4 years ago
4 0
The answer is heart

good luck!
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Calculate the atomic radius, in nm, of the BCC Metal above utilizing the density and the atomic weight provided by examination b
andre [41]

Answer:

radius = 0.2195 nm

Explanation:

l = 2r

r = 0.439/2 = 0.2195

7 0
3 years ago
How many grams are in 0.02 moles of beryllium iodide, BeI2
just olya [345]

Answer:Beryllium iodide has a molar mass of 262.821 g mol−1 , which means that 1 mole of beryllium iodide has a mass of 262.821 g . To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.

Explanation:

3 0
4 years ago
Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
A solid ball has a density of 2.5 g/cm and a volume of 20 cm3. What is the
Svetach [21]

Answer:

50 g

Explanation:

d= m/v

rearranging the above equation

m = d x v

m = 2.5 g x 20 g/cm3

m = 50 g

7 0
3 years ago
? Question
mr_godi [17]

A is the answer

In an ozone molecule, the three atoms must be connected, so there must at least be a single bond between them. Place

dots in pairs around the oxygen atoms until each oxygen atom has eight valence electrons, starting with the atoms on the

outside and doing the central atom last if there are enough. Do not exceed the total number of valence electrons

identified in part A. Remember that the dashes between the oxygen atoms, which represent single bonds, each indicate

the presence of two valence electrons

6 0
3 years ago
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