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zhuklara [117]
3 years ago
12

When two plates of differing densities collide, how might the density of each plate affect which plate is pulled beneath the oth

er?
Physics
1 answer:
OlgaM077 [116]3 years ago
5 0
Pull the plates apart and you will knwo what it is lmaoo
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A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a
xxTIMURxx [149]

Answer:y_{com}=0.707 m

v_{com}=3.713 m/s

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by  first stone in 430 ms

y_1=ut+\frac{at^2}{2}

y_1=0+\frac{g(0.43)^2}{2}

y_1=0.9069 m

Distance traveled by stone 2 in t=430-59=371 ms

y_2=ut+\frac{at^2}{2}

y_2=0+\frac{g(0.0.371)^2}{2}

y_2=0.674 m

velocity of first stone after t=0.43 s

v_1=u+at

v_1=0+9.8\times 0.43=4.214 m/s

velocity of second stone after t=0.371 s

v_2=u+at

v_2=0+9.8\times 0.371=3.63 m/s

Position of Center of mass of system

y=\frac{y_1m_1+y_2m_2}{m_1+m_2}

y=\frac{0.9069\times m+0.674\times 6m}{m+6m}

y=\frac{4.95m}{7m}=0.707 m

Velocity of COM

v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}

v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}

v_{com}=3.713 m/s

6 0
4 years ago
¿Qué entiendes por un fenómeno eléctrico?​
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Answer:

English        

Electrical phenomena are commonplace and unusual events that can be observed and that illuminate the principles of the physics of electricity and are explained by them. Electrical phenomena are a somewhat arbitrary division of electromagnetic phenomena

Los fenómenos eléctricos son eventos comunes e inusuales que se pueden observar y que iluminan los principios de la física de la electricidad y son explicados por ellos. Los fenómenos eléctricos son una división algo arbitraria de los fenómenos electromagnéticos.

6 0
3 years ago
All of the following are bases except
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Answer:

(C) HBr is an acid .......

8 0
3 years ago
Read 2 more answers
If a hockey player starts from rest and accelerates at a rate of 2.1 m/s2 how long does it take him to skate 30m
OLga [1]
Hello!

<span>Let us apply the time function of space, in the uniform uniform motion (UUM)
</span>
Formula: S = S_{o} +  V_{o}* t + a* \frac{t^2}{2}

Data:
S (Final position) = 30 m
So (Initial Position) = 0 m
Vo (Initial velocity) = 0 m/s
t (time) = ? (in seconds)
a (acceleration) = 2.1 m/s²

Solving:
S = S_{o} + V_{o}* t + a* \frac{t^2}{2}
30 = 0 + 0*t + 2.1* \frac{t^2}{2}
30 =  \frac{2.1t^2}{2}
30*2 = 2.1t^2
60 = 2.1t^2
2.1t^2 = 60
t^2 =  \frac{60}{2.1}
t^2 \approx 28.5
t \approx  \sqrt{28.5}
\boxed{\boxed{t \approx 5.3\:s}}\end{array}}\qquad\quad\checkmark

Answer:
<span>C. 5.3s</span>
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4 years ago
When a car’s wheels turn, the wheels push backward on the road. what is it that makes the car go forward?
Iteru [2.4K]
<span>engine makes the car go forward but, it is the engine that makes the wheels go.
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