The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L
<h3>Effect of Pressure on Solubility </h3>
As the <em>pressure </em>of a gas increases, the <em>solubility </em>increases, and as the <em>pressure </em>of a gas decreases, the <em>solubility </em>decreases.
Thus, Solubility varies directly with Pressure
If S represents Solubility and P represents Pressure,
Then we can write that
S ∝ P
Introducing proportionality constant, k
S = kP
S/P = k
∴ We can write that

Where
is the initial solubility
is the initial pressure
is the final solubility
is the final pressure
From the given information



Putting the parameters into the formula, we get



Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L
Learn more on Solubility here: brainly.com/question/4529762