Answer:
C₂ = 0.056 ppm
Explanation:
Given data:
Initial volume = 2.0 mL
Initial concentration = 7.0 ppm
Final volume = 250.0 mL
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ = Final volume
Now we will put the values in formula.
C₁V₁ = C₂V₂
7.0 ppm × 2.0 mL = C₂ × 250.0 mL
C₂ = 14.0 ppm.mL /250.0 mL
C₂ = 0.056 ppm
Answer:through the conduction from magma to water and rocks
Explanation:
Answer:
Piso = 32.17 Torr
Pprop = 5.079 Torr
yprop = 0.1364
yiso = 0.8636
Explanation:
From the question; we can opine that :
- The mole fraction of isopropanol in a mixture of isopropanol and propanol will be 1.
-
The partial pressure of isopropanol will be its mole fraction multiplied by vapor pressure of isopropanol
-
The partial pressure of propanol will be its mole fraction multiplied by vapor pressure of propanol
-
In the vapor, the mole fraction of propanol will be its partial pressure divided by the sum of the two partial pressures
NOW;
When xprop = 0.243; xisopropanol will be 1- 0.243 = 0.757
P°iso = 45.2 Torr at 25 °C so
Piso will be 45.2 × 0.757 = 32.17 Torr
Pprop will be 20.9 × 0.243 = 5.079 Torr
yprop = 5.079/(5.079 +32.17) = 0.1364
yiso = 1-0.1364 = 0.8636
Answer:
0.393 mol/L.
Explanation:
The following data were obtained from the question:
Number of mole of NaOH = 0.550 mol
Volume of solution = 1.40 L
Molarity of NaOH =.?
Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:
Molarity = mole /Volume
With the above formula, we can obtain the molarity of the NaOH solution as follow:
Number of mole of NaOH = 0.550 mol
Volume of solution = 1.40 L
Molarity of NaOH =.?
Molarity = mole / Volume
Molarity of NaOH = 0.55 / 1.4
Molarity of NaOH = 0.393 mol/L
Thus, the molarity of the NaOH solution is 0.393 mol/L.
