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saw5 [17]
3 years ago
7

Need help ASAP! Describes volume?

Chemistry
1 answer:
frutty [35]3 years ago
8 0

Answer:

a definite to indefinite

Explanation:

because if it is in liquid the volume is trusted,but if it is in gas the volume would have multiplied

i think u can pit it well

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A buffer is prepared by adding 12.0g of ammonium chloride (NH4Cl) to 250mL of 1.00 M NH3 solution?The pH is 9.3 Write the net io
solniwko [45]

Answer:- NH_3(aq)+H^+(aq)\rightleftharpoons NH_4^+(aq)

Explanations:- The solution we have is a buffer solution and we know that a buffer solution resists a change in its pH if a strong acid or base is added to it.

Here, the buffer solution we have is of a weak base and it's conjugate acid. So, a strong acid(nitric acid) is added to this buffer then it reacts with the base present in the buffer so that the acid could be neutralized. This is called buffer action.

The net ionic equation is written as:

NH_3(aq)+H^+(aq)\rightleftharpoons NH_4^+(aq)

Note that HNO_3 is a strong acid and nitrate ion is the spectator ion so it is not included in the net ionic equation.

8 0
3 years ago
Chiara knows that weight is affected by gravitational pull. She is putting together a poster to display in her classroom.
Tanya [424]

Answer: A

Explanation: 150 lb * 1/6 = 25 lb

8 0
3 years ago
Read 2 more answers
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photoshop1234 [79]
I think it could be C maybeee though
6 0
3 years ago
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
Elden [556K]

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

7 0
2 years ago
Molar mass of Ag2SO4<br><br> Full work Pls
IceJOKER [234]
This would be the molar mass.

5 0
3 years ago
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