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nikdorinn [45]
3 years ago
15

A 50 kg boy is at the edge of a circular platform of radius 4.0 m which is rotating freely

Physics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

0.62 rad/s

Explanation:

Angular momentum is conserved.

I₁ ω₁ = I₂ ω₂

where I is moment of inertia and ω is angular velocity.

The total moment of inertia is the sum of the platform's inertia and the boy's.

(I + m r₁²) ω₁ = (I + m r₂²) ω₂

Given I = 1000 kg m², m = 50 kg, r₁ = 4.0 m, r₂ = 3.0 m, and ω₁ = 0.5 rad/s:

(1000 + 50 (4.0)²) (0.5) = (1000 + 50 (3.0)²) ω₂

900 = 1450 ω₂

ω₂ = 0.62 rad/s

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