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ohaa [14]
3 years ago
10

You need to produce a buffer solution that has a ph of 5.16. you already have a solution that contains 10. mmol (millimoles) of

acetic acid. how many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? the pka of acetic acid is 4.74.
Chemistry
1 answer:
tatiyna3 years ago
4 0
PH= pKa + log( conjugate base/ conjugate acid)
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How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
Lithium reacts spontaneously with bromine to produce lithium bromide. Write the balanced chemical equation for the reaction. (Us
nekit [7.7K]
Answer:
___________________________________________________
       
            "     2 Li + Br2<span> ----> 2 LiBr     "  .
___________________________________________________</span>
3 0
3 years ago
Which has a higher melting point, NaBr or KBr
Blababa [14]
NaBr melting point : 1,377°F (774C)
KBr: 1,353°F (734C)
7 0
4 years ago
Read 2 more answers
why is the frequency of the C=O stretch in the hydrogenation product higher than in ethyl cinnamate?
antiseptic1488 [7]
The hydrogenation of ethyl cinnamate will result to an ester which can be a racemic mixture of products or just a meso compound depending on the structure of the ethyl cinnamate (cis or trans). The ester will produce a frequency of C=O stretch of <span>1750 - 1735 (s.</span>
7 0
3 years ago
how does resistance change with temperature? is there more resistance or less resistance at higher temperatures?
timofeeve [1]

The resistance has a linear relationship with temperature because it increases as temperatures increases.

<h3>What is temperature?</h3>

Temperature refers to the activity (motion or thermal energy) in the atoms that form molecules.

The resistance of an electric conductor increases as the temperature increases since the thermal energy of subatomic electrons also increases.

In conclusion, the resistance has a linear relationship with temperature because it increases as temperatures increases.

Learn more about resistance here:

brainly.com/question/1834200

#SPJ1

8 0
2 years ago
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