Answer:
4.4 m/s
Explanation:
momentum is always conserved so we can use conversation of momentum to solve the question, also momentum is a vector quantity ( it has magnitude and direction) which is the product of the bodies mass and velocity.
conservation law of momentum relates by the formula below:
momentum before collision = momentum after collision
M1U1 + M2U2 = M1V1 + M2V2
in the case of this two, the formula becomes
M1U1 + M2U2 = V (M1 + M2) since she jumped into his arm
there masses are M1 = 75.6 kg M2 = 59 kg and their velocities are U1 = 3.7 m/s and U2 = 5.4 m/s, their common velocity after collision = V since their motion is backward the formula becomes
-M1U1 - M2U2 = V(M1 + M2)
substitute the values into the equations
(-75.6 × 3.7 ) + (- 59 × 5.4) = V ( 75.6 + 59)
- 598.32 = 134.6 V
divide both side by 134.6
V = - 598.32 / 134.6 = -4.445 m/s = -4.4 m/s to nearest tenth the negative means in the same backward direction
We are given
m = mass of the object
r = distance from the center of the planet
r <span>≥ rplanet
We are asked for the
ve = escape velocity
The escape velocity
ve = </span>√ (2Gm/r)
<span>
</span>
Explanation:
It is given that,
Force exerted by a boy, F = 11.8 N
Angle above the horizontal,
Mass of the sled, m = 6.15 kg
Distance moved, d = 2.75 m
Initial speed, u = 0.37 m/s
Let W is the work done by the boy. Using the expression for the work done to find it as :
W = 28.65 joules
Let v is the final speed of the sled. Using the work energy theorem to find it. It states that the work done is equal to the change in kinetic energy of an object. It is given by :
v = 3.07 m/s
So, the final speed of the sled after it moves 2.75 m is 3.07 m/s. Hence, this is the required solution.