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Bingel [31]
3 years ago
5

Examine the equation of a reversible reaction.

Chemistry
2 answers:
Alex3 years ago
8 0

Answer:

The correct answer for the reverse reaction is the third option starting from top.

Explanation:

If we examine the given chemical equation:

2SO2 + O2 ⇌ 2SO3

The double arrow indicates that the reaction goes in both directions:

2SO2 + O2 -> 2SO3

2SO3 -> 2SO2 + O2

However, the closest option for the real situation would be the product from the semirreaction reacting in turn with oxygen:

2SO3 + O2 -> 2SO2

Thus, the correct answer is the third.

morpeh [17]3 years ago
6 0

Answer:

2SO3 -> 2SO2 + O2 (not shown in the options)

Explanation:

In a reversible reaction, reactants react to produce products and products react to produce reactants, simultaneously.

Given the reversible reaction:

2SO2 + O2 ⇌ 2SO3

It has a forward reaction:

2SO2 + O2 -> 2SO3

and a reverse reaction:

2SO2 + O2 <- 2SO3

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Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.6 g of methane is
lianna [129]

Answer:

21.6 g

Explanation:

The reaction that takes place is:

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First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
  • 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:

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