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3 years ago

14

Which property would be least helpful in determining whether a substance is a metal or a nonmetal?

2 answers:

lidiya [134]3 years ago

8 0

Answer:

Thermal and electric conductivities.

Explanation:

Metals tends to have high thermal and electric conductivities in comparison with nonmentals.

Marina86 [1]3 years ago

5 0

The answer is state.

That is the state would be least helpful in determining whether a substance is a metal or a nonmetal. The state can only tells that a compound is liquid, gas or solid. But it can't tell whether a substance is metal or non-metal. So it is the least helpful in determining whether a compound is metal or non-metal.

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Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

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Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

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Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

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